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An owl is 7 metres above ground level, in a tree - HSC - SSCE Mathematics Standard - Question 12 - 2019 - Paper 1

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An owl is 7 metres above ground level, in a tree. The owl sees a mouse on the ground at an angle of depression of 32°. How far must the owl fly in a straight line t... show full transcript

Worked Solution & Example Answer:An owl is 7 metres above ground level, in a tree - HSC - SSCE Mathematics Standard - Question 12 - 2019 - Paper 1

Step 1

Calculate the Horizontal Distance

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Answer

To find the horizontal distance to the mouse, we can use the formula relating the angle of depression, the height (opposite side), and the horizontal distance (adjacent side).

Using trigonometry, we know that: tan(θ)=oppositeadjacent\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}

Here, ( \theta = 32° ) and the height of the owl (opposite side) is 7 m. Therefore, we have:

tan(32°)=7d\tan(32°) = \frac{7}{d}

Where ( d ) is the horizontal distance to the mouse. Rearranging gives us:

d=7tan(32°)d = \frac{7}{\tan(32°)}

Calculating this value yields approximately:

d7/0.6248711.2md \approx 7 / 0.62487 \approx 11.2 m

Step 2

Calculate the Straight-Line Distance

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Answer

Now, we can use the Pythagorean theorem to find the straight-line distance (hypotenuse) the owl must fly.

We define the straight-line distance ( s ):

s=(height)2+(horizontal distance)2s = \sqrt{(\text{height})^2 + (\text{horizontal distance})^2}

Substituting the known values:

s=(7)2+(11.2)2s = \sqrt{(7)^2 + (11.2)^2}

Calculating this gives:

s=49+125.44=174.4413.2ms = \sqrt{49 + 125.44} = \sqrt{174.44} \approx 13.2 m

Step 3

Conclusion

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Answer

Therefore, the owl must fly approximately 13.2 metres in a straight line to catch the mouse.

The correct answer is D. 13.2 m.

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