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can be concluded from the results of this investigation that manuka honey promotes the expression of elongation factor protein (EF-Tu) - VCE - SSCE Biology - Question 38 - 2020 - Paper 1
Question 38
can be concluded from the results of this investigation that manuka honey promotes the expression of elongation factor protein (EF-Tu). reduces the ability of S. aur... show full transcript
Worked Solution & Example Answer:can be concluded from the results of this investigation that manuka honey promotes the expression of elongation factor protein (EF-Tu) - VCE - SSCE Biology - Question 38 - 2020 - Paper 1
Step 1
promotes the expression of elongation factor protein (EF-Tu)
Answer
Manuka honey has been shown to stimulate the expression of elongation factor Tu (EF-Tu). EF-Tu plays a crucial role in protein synthesis within bacterial cells, which can enhance the antibacterial effectiveness of manuka honey against pathogens like S. aureus.
Step 2
reduces the ability of S. aureus to adapt to changing conditions
Answer
Research indicates that manuka honey impairs the adaptability of S. aureus to environmental stressors. This interference potentially leads to a decreased survival rate of the bacteria when exposed to conditions that would typically challenge its resilience.
Step 3
is more effective than jelly bush honey at limiting the growth of S. aureus
Answer
Comparative studies demonstrate that manuka honey exhibits superior antimicrobial properties to jelly bush honey when it comes to inhibiting the growth of S. aureus. This effectiveness can be attributed to its higher concentration of unique bioactive compounds.
Step 4
heals wounds faster than jelly bush honey and much faster than when no honey is added
Answer
Clinical evidence suggests that wounds treated with manuka honey show accelerated healing compared to those treated with jelly bush honey or no honey at all. This may be due to manuka honey's enhanced antibacterial effects and its ability to promote tissue regeneration.