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Red-green colour blindness is an X-linked recessive trait with the alleles $X^R$: normal color vision $X^e$: red-green colour blind Examine the following pedigree - VCE - SSCE Biology - Question 16 - 2011 - Paper 1

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Question 16

Red-green-colour-blindness-is-an-X-linked-recessive-trait-with-the-alleles-$X^R$:-normal-color-vision-$X^e$:-red-green-colour-blind--Examine-the-following-pedigree-VCE-SSCE Biology-Question 16-2011-Paper 1.png

Red-green colour blindness is an X-linked recessive trait with the alleles $X^R$: normal color vision $X^e$: red-green colour blind Examine the following pedigree. ... show full transcript

Worked Solution & Example Answer:Red-green colour blindness is an X-linked recessive trait with the alleles $X^R$: normal color vision $X^e$: red-green colour blind Examine the following pedigree - VCE - SSCE Biology - Question 16 - 2011 - Paper 1

Step 1

II3 must be $X^R X^R$.

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Answer

To determine if II3 can be XRXRX^R X^R, we analyze the pedigree. Since II2 is normal (filled square), and both parents can contribute an X chromosome, if II2 is XRXeX^R X^e, II3 cannot be XRXRX^R X^R since there’s a chance II3 could inherit XeX^e. Thus, this statement is false.

Step 2

II4 must be $X^R X^e$.

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Answer

To evaluate II4, we notice II3 (male) cannot carry XRX^R while being normal, implying that II4 presents a genotype that includes XeX^e for the colorblind trait. Thus, II4 most likely must be XRXeX^R X^e, making this statement true.

Step 3

II4 has a two in three chance of being $X^R X^R$.

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Answer

For II4 to have a two in three chance of being XRXRX^R X^R, considering two males contributing an X chromosome to II4, we must conclude that individual probabilities must align directly with direct pattern inheritance, giving a greater likelihood of being XRXeX^R X^e instead. Hence, this statement is false.

Step 4

IV1 has a one in four chance of being colour blind.

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Answer

Since IV1 inherits X chromosomes from both parents, one being XeX^e, the likelihood of inheriting the colour blind trait is 1 in 4, as it can be XRXRX^R X^R, XRXeX^R X^e, or XeXeX^e X^e. Therefore, this statement is true.

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