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6. Methane gas, CH₄, can be captured from the breakdown of waste in landfills - VCE - SSCE Chemistry - Question 6 - 2020 - Paper 1

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6. Methane gas, CH₄, can be captured from the breakdown of waste in landfills. CH₄ is also a primary component of natural gas. CH₄ can be used to produce energy thro... show full transcript

Worked Solution & Example Answer:6. Methane gas, CH₄, can be captured from the breakdown of waste in landfills - VCE - SSCE Chemistry - Question 6 - 2020 - Paper 1

Step 1

a. Write the equation for the incomplete combustion of CH₄ to produce carbon monoxide, CO.

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Answer

The equation for the incomplete combustion of methane (CH₄) producing carbon monoxide (CO) can be represented as:

CH4(g)+32O2(g)CO(g)+2H2O(l)\text{CH}_4(g) + \frac{3}{2} \text{O}_2(g) \rightarrow \text{CO}(g) + 2 \text{H}_2\text{O}(l)

Alternatively, it can also be written as:

2CH4(g)+3O2(g)2CO(g)+4H2O(l)2 \text{CH}_4(g) + 3 \text{O}_2(g) \rightarrow 2 \text{CO}(g) + 4 \text{H}_2\text{O}(l)

Step 2

b. If 20.0 g of CH₄ is kept in a 5.0 L sealed container at 25 °C, what would be the pressure in the container?

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Answer

First, convert the mass of CH₄ to moles:

n(CH4)=20.0g16.0g/mol=1.25moln(CH_4) = \frac{20.0\, g}{16.0\, g/mol} = 1.25\, mol

Using the ideal gas law, apply it as follows:

  • R = 8.31 J/(mol·K)
  • V = 5.0 L = 0.005 m³ (since 1 L = 0.001 m³)
  • T = 25 °C = 298 K (convert to Kelvin)

Now apply the ideal gas law:

P=nRTV=(1.25mol)(8.31J/(molK))(298K)0.005m3=6.20×102kPaP = \frac{nRT}{V} = \frac{(1.25\, mol)(8.31\, J/(mol·K))(298\, K)}{0.005\, m³} = 6.20 \times 10^2 \text{kPa}

Step 3

c. Calculate the percentage of the Bunsen burner’s energy that is lost to the environment.

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Answer

To determine this percentage, first calculate the energy released during the combustion of CH₄. The heat absorbed by the water can be calculated as:

q=mcΔTq = m c \Delta T

where:

  • m=350.0gm = 350.0\, g (mass of water)
  • c=4.18J/g°Cc = 4.18\, J/g·°C (specific heat capacity of water)
  • ΔT=32.3°C20°C=12.3°C\Delta T = 32.3 °C - 20 °C = 12.3 °C

Thus: q=350.0g×4.18J/g°C×12.3°C=18152.7Jq = 350.0\, g \times 4.18\, J/g·°C \times 12.3 °C = 18152.7\, J

Next, calculate the energy produced from the combustion of 0.485 g of CH₄:

  • Combustion of CH₄ releases about 890 kJ/mol. First, convert the mass to moles:

n(CH4)=0.485g16.0g/mol=0.03031moln(CH_4) = \frac{0.485\, g}{16.0\, g/mol} = 0.03031\, mol

Energy produced: E=0.03031mol×890kJ/mol=26.93kJ=26930JE = 0.03031\, mol \times 890\, kJ/mol = 26.93\, kJ = 26930\, J

Finally, the percentage of energy lost to the environment is given by: Percentage lost=Energy lostEnergy produced×100=18152.726930×10067.4%\text{Percentage lost} = \frac{\text{Energy lost}}{\text{Energy produced}} \times 100 = \frac{18152.7}{26930} \times 100 \approx 67.4\%

Step 4

d. Compare the environmental impact of CH₄ obtained from landfill to the environmental impact of CH₄ obtained from natural gas.

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Answer

Both sources of methane (landfill and natural gas) produce carbon dioxide when combusted, contributing to greenhouse gas emissions. However, there are significant differences:

Similarity:

  • Both sources emit CO₂ during combustion, impacting climate change.
  • Both sources contain trace amounts of nitrogen and sulfur, which can lead to the formation of nitrogen oxides (NOₓ).

Difference:

  • Methane from landfills can be produced renewably and is often considered a lower carbon source, while that from natural gas extraction tends to be more damaging.
  • Extraction of fossil fuels can result in significant environmental damage, including habitat destruction and increased atmospheric CO₂ levels. Methane from landfill is already part of the waste cycle.
  • Additionally, landfill methane is often captured and utilized, thus preventing it from contributing to ozone layer depletion. In contrast, natural gas mining may cause more pollution and related health risks.

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