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In the 19th century, relative atomic masses (RAMs) were determined by gravimetric analysis - VCE - SSCE Chemistry - Question 4 - 2004 - Paper 1

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In the 19th century, relative atomic masses (RAMs) were determined by gravimetric analysis. In a particular experiment, to determine the RAM of a metal (X), 3.27 g o... show full transcript

Worked Solution & Example Answer:In the 19th century, relative atomic masses (RAMs) were determined by gravimetric analysis - VCE - SSCE Chemistry - Question 4 - 2004 - Paper 1

Step 1

Calculate the mass of oxygen reacted

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Answer

The mass of oxygen that reacted can be calculated by subtracting the mass of the metal X from the total mass of the oxide produced:

extMassofO=extMassofXOextMassofX=4.07g3.27g=0.80g ext{Mass of O} = ext{Mass of XO} - ext{Mass of X} = 4.07 \, g - 3.27 \, g = 0.80 \, g

Step 2

Calculate the moles of oxygen

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Using the molar mass of oxygen (approximately 16 g/mol), we can calculate the moles of oxygen:

extMolesofO=massmolar mass=0.80g16g/mol=0.05mol ext{Moles of O} = \frac{\text{mass}}{\text{molar mass}} = \frac{0.80 \, g}{16 \, g/mol} = 0.05 \, mol

Step 3

Determine the moles of metal X

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Answer

From the formula XO, we see that for every mole of metal X, there is one mole of oxygen. Therefore, the moles of metal X will also be 0.05 mol.

Step 4

Calculate the RAM of metal X

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Answer

Now, we can calculate the RAM of metal X using the formula:

RAM of X=mass of Xmoles of X=3.27g0.05mol=65.4g/mol\text{RAM of X} = \frac{\text{mass of X}}{\text{moles of X}} = \frac{3.27 \, g}{0.05 \, mol} = 65.4 \, g/mol

Step 5

Select the correct option

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Answer

Based on the calculation, the RAM of X is 65.4 g/mol, which corresponds to option C.

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