Which one of the following best represents the changes in concentration when the equilibrium mixture is diluted at time $t_2$?
A - VCE - SSCE Chemistry - Question 8 - 2012 - Paper 1
Question 8
Which one of the following best represents the changes in concentration when the equilibrium mixture is diluted at time $t_2$?
A.
concentration
Fe(SCN)^{2+}
B.
con... show full transcript
Worked Solution & Example Answer:Which one of the following best represents the changes in concentration when the equilibrium mixture is diluted at time $t_2$?
A - VCE - SSCE Chemistry - Question 8 - 2012 - Paper 1
Step 1
A. concentration Fe(SCN)^{2+} At time t_2
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
When the equilibrium mixture is diluted at time t2, the concentration of Fe(SCN)^{2+} will initially decrease due to the dilution process.
Step 2
B. concentration Fe^{3+} At time t_2
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
As the equilibrium shifts to compensate for the decrease in the concentration of Fe(SCN)^{2+},theconcentrationofFe3+ will increase, as more Fe^{3+}$ will dissociate to maintain equilibrium.
Step 3
C. concentration SCN^{-} At time t_2
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Similar to Fe^{3+},theconcentrationofSCN− will also increase as it dissociates from the complex to shift the equilibrium.
Step 4
D. concentration Overall Assessment
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Thus, the best representation of these changes in concentration when the equilibrium mixture is diluted at time t2 corresponds to option B in the diagram.