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Question 9 An expression for the equilibrium constant for this reaction is 2ClF(g) ⇌ 3F₂(g) + Cl₂(g) ΔH = negative A - VCE - SSCE Chemistry - Question 9 - 2003 - Paper 1

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Question 9

Question-9-An-expression-for-the-equilibrium-constant-for-this-reaction-is--2ClF(g)-⇌-3F₂(g)-+-Cl₂(g)--ΔH-=-negative--A-VCE-SSCE Chemistry-Question 9-2003-Paper 1.png

Question 9 An expression for the equilibrium constant for this reaction is 2ClF(g) ⇌ 3F₂(g) + Cl₂(g) ΔH = negative A. \[ \frac{[ClF]^2}{[F_2]^3[C1]} \] B. \[ ... show full transcript

Worked Solution & Example Answer:Question 9 An expression for the equilibrium constant for this reaction is 2ClF(g) ⇌ 3F₂(g) + Cl₂(g) ΔH = negative A - VCE - SSCE Chemistry - Question 9 - 2003 - Paper 1

Step 1

An expression for the equilibrium constant for this reaction is

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Answer

The equilibrium constant KK for a reaction at equilibrium is expressed in terms of the concentrations of the reactants and products raised to the power of their coefficients in the balanced equation. For the reaction:

2ClF(g)⇌3F2(g)+Cl2(g)2ClF(g) \rightleftharpoons 3F_2(g) + Cl_2(g)

The expression for the equilibrium constant is given by:

K=[F2]3[Cl2][ClF]2K = \frac{[F_2]^3 [Cl_2]}{[ClF]^2}

Thus, the correct answer is D: [ \frac{2[ClF]}{[F_2]^3} ], which represents the reciprocal of the derived expression.

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