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Consider the following information - VCE - SSCE Chemistry - Question 6 - 2007 - Paper 1

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Consider the following information. • Ethanol burns in excess air according to the following equation. C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g) ΔH = -1364 kJ mol^-1 ... show full transcript

Worked Solution & Example Answer:Consider the following information - VCE - SSCE Chemistry - Question 6 - 2007 - Paper 1

Step 1

Calculate the minimum amount of energy, in kJ, required to heat 550 g of water and the pot from 18.5°C to 100.0°C.

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Answer

To calculate the total energy required, we must sum the energy needed to heat both the water and the aluminum pot.

  1. Energy for Water:

    Using the formula:

    Q=mcriangleTQ = mc riangle T

    where:

    • mm = mass of water = 550 g,

    • cc = specific heat capacity of water = 4.18 J g^{-1} °C^{-1},

    • riangleT riangle T = change in temperature = 100.0°C - 18.5°C = 81.5°C.

    Qwater=550imes4.18imes81.5=198,165extJ=198.2extkJQ_{water} = 550 imes 4.18 imes 81.5 = 198,165 ext{ J} = 198.2 ext{ kJ}

  2. Energy for Aluminium Pot:

    For the aluminum pot, we use the same formula:

    where:

    • mm = mass of aluminum = 150 g,
    • cc = specific heat capacity of aluminum = 9.000 J g^{-1} °C^{-1}.

    Qaluminium=150imes9.000imes81.5=1,116,750extJ=1116.8extkJQ_{aluminium} = 150 imes 9.000 imes 81.5 = 1,116,750 ext{ J} = 1116.8 ext{ kJ}

  3. Total Energy Required:

    Qtotal=Qwater+Qaluminium=198.2+1116.8=1315extkJQ_{total} = Q_{water} + Q_{aluminium} = 198.2 + 1116.8 = 1315 ext{ kJ}

Thus, the minimum energy required is approximately 1315 kJ.

Step 2

Calculate the mass, in g, of ethanol that needs to be completely burnt to provide this energy.

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Answer

To determine the mass of ethanol required to provide this energy:

  1. Use the heat of combustion of ethanol:

    Given that the heat of combustion for ethanol is ΔH = -1364 kJ/mol.

  2. Calculate the moles of ethanol needed:

    Using the formula:

    ext{moles} = rac{Q_{needed}}{ ext{ΔH}} = rac{1315 ext{ kJ}}{1364 ext{ kJ/mol}} = 0.965 ext{ mol}

  3. Calculate the mass of ethanol:

    The molar mass of ethanol (C2H5OH) is 46.07 g/mol.

    extmass=extmolesimesextmolarmass=0.965imes46.07=44.42extg ext{mass} = ext{moles} imes ext{molar mass} = 0.965 imes 46.07 = 44.42 ext{ g}

Thus, 44.42 g of ethanol needs to be burnt.

Step 3

Calculate the mass, in g, of ethanol that needs to be burnt in practice to heat the water and the pot from 18.5°C to 100.0°C.

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Answer

In this part, we take into account that only 35% of the energy released from the combustion of ethanol is effectively used:

  1. Calculate the effective energy released:

    Qeffective=0.35imesQneeded=0.35imes1315extkJ=460.25extkJQ_{effective} = 0.35 imes Q_{needed} = 0.35 imes 1315 ext{ kJ} = 460.25 ext{ kJ}

  2. Calculate the moles of ethanol for effective energy:

    ext{moles} = rac{Q_{effective}}{ ext{ΔH}} = rac{460.25 ext{ kJ}}{1364 ext{ kJ/mol}} = 0.337 ext{ mol}

  3. Calculate the mass of ethanol burned in practice:

    extmass=extmolesimesextmolarmass=0.337imes46.07=15.53extg ext{mass} = ext{moles} imes ext{molar mass} = 0.337 imes 46.07 = 15.53 ext{ g}

Thus, 15.53 g of ethanol needs to be burnt in practice.

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