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The 1H NMR spectrum of an organic compound has three unique sets of peaks: a single peak, seven peaks (septet), and two peaks (doublet) - VCE - SSCE Chemistry - Question 30 - 2021 - Paper 1

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The 1H NMR spectrum of an organic compound has three unique sets of peaks: a single peak, seven peaks (septet), and two peaks (doublet). The compound is A. 3-methy... show full transcript

Worked Solution & Example Answer:The 1H NMR spectrum of an organic compound has three unique sets of peaks: a single peak, seven peaks (septet), and two peaks (doublet) - VCE - SSCE Chemistry - Question 30 - 2021 - Paper 1

Step 1

Identify the Single Peak

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Answer

The single peak in the NMR spectrum typically represents a proton that is in a unique environment, often part of a functional group such as a methyl group (–CH3) adjacent to a carbon chain.

Step 2

Analyze the Septet

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Answer

The septet usually indicates a proton that is adjacent to six equivalent protons. This corresponds to a (n+1) rule in NMR, where 'n' refers to how many protons are on adjacent carbons. This suggests the presence of a methyl group next to a methylene group (–CH2–) within a structure.

Step 3

Evaluate the Doublet

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Answer

The doublet indicates a proton that is coupled to one other equivalent proton. This could suggest the presence of a methine group (–CH) next to a methyl group.

Step 4

Determine the Most Likely Structure

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Answer

Given that we need a compound with the aforementioned characteristics, we analyze the options provided:

  • 3-methyl butanoic acid: This would analyze to potentially yield a single peak, but may not account for all peak types.
  • 2-methyl propanoic acid: This compound fits well with having a septet and additional environments that match the peak counts described.
  • 2-chloro-2-methylpropane: Given the presence of chlorine substituents, it may alter peak patterns.
  • 1,2-dichloro-2-methylpropane: Similar reasoning as the previous, might affect the NMR.

Thus, the answer is B. 2-methyl propanoic acid.

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