Paraffin oil contains a mixture of high molecular mass alkanes - VCE - SSCE Chemistry - Question 5 - 2007 - Paper 1

Alumina acts as a catalyst in this reaction, increasing the rate at which the molecules break down into smaller alkanes and alkenes.

The balanced equation for the conversion of C17H36 to ethene (C2H4) can be represented as follows:

$C_{17}H_{36} \rightarrow C_{2}H_{4} + C_{15}H_{32}$

where C15H32 represents another alkane.

The balanced equation for the addition of bromine to ethene is as follows:

$C_{2}H_{4} + Br_{2} \rightarrow C_{2}H_{4}Br_{2}$

The balanced equation for the complete combustion of ethene is:

$C_{2}H_{4} + 3O_{2} \rightarrow 2CO_{2} + 2H_{2}O$

The balanced equation for the reaction of ethene with steam, facilitated by a catalyst, is:

$C_{2}H_{4} + H_{2}O \rightarrow C_{2}H_{5}OH$

This reaction produces ethanol.

Compound A and B can be represented as follows:

• Compound A:

  • Structural Formula:

  ![A: Structural Formula Here]

  • Systematic Name: 1,2-dibromoethane

• Compound B:

  • Structural Formula:

  ![B: Structural Formula Here]

  • Systematic Name: 1,1-dibromoethane

Compound C, the acidic compound, can be represented as follows:

• Compound C:

  • Structural Formula:

  ![C: Structural Formula Here]

  • Systematic Name: Propanoic acid