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A bomb calorimeter may be calibrated using a substance with a well-known heat of combustion - VCE - SSCE Chemistry - Question 3 - 2004 - Paper 1

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A bomb calorimeter may be calibrated using a substance with a well-known heat of combustion. A commonly used calibrating agent is benzoic acid (C7H6O2) which has a h... show full transcript

Worked Solution & Example Answer:A bomb calorimeter may be calibrated using a substance with a well-known heat of combustion - VCE - SSCE Chemistry - Question 3 - 2004 - Paper 1

Step 1

Calculate the amount of benzoic acid in moles

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Answer

The molar mass of benzoic acid (C7H6O2) is calculated as follows:

  • Carbon (C): 7 × 12.01 g/mol = 84.07 g/mol
  • Hydrogen (H): 6 × 1.008 g/mol = 6.048 g/mol
  • Oxygen (O): 2 × 16.00 g/mol = 32.00 g/mol

Thus, the total molar mass:

RMMbenzoicacid=84.07+6.048+32.00=122.12g/molRMM_{benzoic\,acid} = 84.07 + 6.048 + 32.00 = 122.12 \, g/mol

Now, calculate the number of moles of benzoic acid:

extmolesofbenzoicacid=2.50g122.12g/mol=0.0205moles ext{moles of benzoic acid} = \frac{2.50 \, g}{122.12 \, g/mol} = 0.0205 \, moles

Step 2

Calculate the energy released

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Answer

The energy released upon the complete combustion of the benzoic acid can be calculated using its heat of combustion:

extenergy=0.0205moles×3227kJ/mol=66.1kJ ext{energy} = 0.0205 \, moles \times 3227 \, kJ/mol = 66.1 \, kJ

Step 3

Calculate the calibration factor

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Finally, the calibration factor for the calorimeter can be determined using the observed temperature rise:

CF=66.1kJ8.90°C=7.43kJ/°CCF = \frac{66.1 \, kJ}{8.90 \, °C} = 7.43 \, kJ/°C

This is the calibration factor of the calorimeter.

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