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Question 28
If 0.1 mol of ethanoic acid and 0.1 mol of methyl methanoate were completely combusted in two separate closed vessels under identical conditions, the Maxwell-Boltzma... show full transcript
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In this question, we need to analyze the implications of combusting equal moles of two different compounds, ethanoic acid and methyl methanoate, in identical conditions.
Maxwell-Boltzmann Distribution: The Maxwell-Boltzmann distribution describes the distribution of speeds (or kinetic energies) of particles in a gas. Since ethanoic acid has a larger molecular structure compared to methyl methanoate, the combustion of ethanoic acid would likely produce a broader distribution due to greater molecular complexity.
Chemical Energy Consideration: The released chemical energy is influenced by the structure and energy content of the reactants. Ethanoic acid, being a carboxylic acid, may have a higher overall enthalpy compared to that of the ester methyl methanoate, thus resulting in more energy release, which may also reflect in the Maxwell-Boltzmann distribution, emphasizing a broader spread in kinetic energy.
In conclusion, after analyzing both the Maxwell-Boltzmann distribution and the chemical energy aspect, the correct option is C. The distribution from the ethanoic acid combustion would be broader and exhibit higher chemical energy compared to that of methyl methanoate.
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