To find the energy absorbed by water, we use:
Q=mcΔT
where:
- m=350.0g (mass of water)
- c=4.18J/g°C (specific heat of water)
- ΔT=32.3°C−20°C=12.3°C
Thus:
Q=(350.0g)(4.18J/g°C)(12.3°C)=18,264.3J
Next, we calculate the energy released from the combustion of 0.485 g of CH₄:
- The molar mass of CH₄ is 16.0 g/mol, so:
n(CH4)=16.0g/mol0.485g=0.0303mol
- The heat of combustion for CH₄ is approximately 890 kJ/mol, thus:
Qcombustion=n(CH4)×890 kJ/mol=0.0303mol×890kJ/mol=26.92kJ=26,920J
Percentage of energy lost is given by:
Percentage Lost=(QcombustionQcombustion−Q)×100
Substituting the values:
Percentage Lost=(26,920J26,920J−18,264.3J)×100=32.42%