A helium balloon is inflated to a volume of 5.65 L and a pressure of 10.2 atm at a temperature of 25 °C - VCE - SSCE Chemistry - Question 16 - 2012 - Paper 1
Question 16
A helium balloon is inflated to a volume of 5.65 L and a pressure of 10.2 atm at a temperature of 25 °C.
The amount of helium, in moles, in the balloon is
A. 0.023
B... show full transcript
Worked Solution & Example Answer:A helium balloon is inflated to a volume of 5.65 L and a pressure of 10.2 atm at a temperature of 25 °C - VCE - SSCE Chemistry - Question 16 - 2012 - Paper 1
Step 1
Calculate the temperature in Kelvin
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Answer
To convert the temperature from Celsius to Kelvin, we use the formula:
T(K)=T(°C)+273.15
Substituting the given value:
T=25+273.15=298.15K
Step 2
Use the Ideal Gas Law
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Answer
The Ideal Gas Law is given by:
PV=nRT
where:
P = pressure in atm = 10.2 atm
V = volume in L = 5.65 L
n = number of moles of gas
R = ideal gas constant = 0.0821 L·atm/(K·mol)
T = temperature in Kelvin = 298.15 K
Step 3
Rearrange the Ideal Gas Law to solve for n
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Answer
Rearranging the formula gives:
n=RTPV
Step 4
Substitute the values into the equation
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Answer
Substituting the known values into the equation:
n=(0.0821 L\cdotpatm/(K\cdotpmol))(298.15 K)(10.2 atm)(5.65 L)
Step 5
Calculate the number of moles
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Answer
Calculating it step-by-step:
Calculate the numerator:
10.2×5.65=57.63
Calculate the denominator:
0.0821×298.15≈24.475
Finally, the number of moles n is:
n=24.47557.63≈2.35
This value rounds to 2.36 moles, which corresponds to option C.