The molar volume of oxygen, in L, at 1.00 atmosphere and 100°C, is closest to A - VCE - SSCE Chemistry - Question 2 - 2006 - Paper 1

To find the molar volume at 100°C and 1 atm, we utilize the Ideal Gas Law:

$PV = nRT$

Where:

• P = pressure (1 atm)
• V = volume (to find)
• n = number of moles (1 mole)
• R = ideal gas constant (0.0821 L·atm/(K·mol))
• T = temperature in Kelvin (100°C = 373.15 K)

Rearranging gives us:

$V = \frac{nRT}{P}$

Substituting the known values:

$V = \frac{(1\, mol)(0.0821\, L\cdot atm/(K\cdot mol))(373.15\, K)}{1\, atm} \approx 30.6\, L$

Thus, the closest option for the molar volume of oxygen at these conditions is 30.6 L.

Based on the calculations, the closest value for the molar volume of oxygen at 1.00 atmosphere and 100°C is:

A. 30.6