1 L of octane has a mass of 703 g at SLC - VCE - SSCE Chemistry - Question 22 - 2021 - Paper 1

Next, we need to find out how much energy is released when 1 L of octane is burned. The energy of combustion of octane is approximately 47.2 MJ/kg. We first convert the volume of octane to mass:

1 L of octane = 703 g = 0.703 kg

Then, the energy released from this mass of octane is:

$$\text{Energy Released} = 0.703 \text{ kg} \times 47.2 \text{ MJ/kg} = 33.11 \text{ MJ}$$

Finally, we can determine how many liters of octane are needed to provide 2112 MJ of energy:

$$\text{Required Volume} = \frac{\text{Total Energy Required}}{\text{Energy Released per L}}$$

Here, we need to find out how many liters will provide the necessary total energy:

$$\text{Required Volume} = \frac{2112 \text{ MJ}}{33.11 \text{ MJ/L}} \approx 63.76 \text{ L}$$

Rounding this value, we find that the volume of octane required is approximately 62.7 L.