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100 mL of an 0.0100 M aqueous solution of calcium hydroxide will absorb carbon dioxide according to the equation Ca(OH)2(aq) + 2 CO2(g) ⇌ Ca(HCO3)2(aq) The maximum volume, in mL, at STP of CO2 that could be absorbed by the solution is A - VCE - SSCE Chemistry - Question 12 - 2002 - Paper 1

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Question 12

100-mL-of-an-0.0100-M-aqueous-solution-of-calcium-hydroxide-will-absorb-carbon-dioxide-according-to-the-equation--Ca(OH)2(aq)-+-2-CO2(g)-⇌-Ca(HCO3)2(aq)--The-maximum-volume,-in-mL,-at-STP-of-CO2-that-could-be-absorbed-by-the-solution-is--A-VCE-SSCE Chemistry-Question 12-2002-Paper 1.png

100 mL of an 0.0100 M aqueous solution of calcium hydroxide will absorb carbon dioxide according to the equation Ca(OH)2(aq) + 2 CO2(g) ⇌ Ca(HCO3)2(aq) The maximum... show full transcript

Worked Solution & Example Answer:100 mL of an 0.0100 M aqueous solution of calcium hydroxide will absorb carbon dioxide according to the equation Ca(OH)2(aq) + 2 CO2(g) ⇌ Ca(HCO3)2(aq) The maximum volume, in mL, at STP of CO2 that could be absorbed by the solution is A - VCE - SSCE Chemistry - Question 12 - 2002 - Paper 1

Step 1

Calculate moles of Ca(OH)₂

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Answer

First, determine the number of moles of calcium hydroxide in the solution. The formula to calculate moles is:

n=C×Vn = C \times V

where:

  • nn is the number of moles,
  • CC is the concentration (0.0100 M),
  • VV is the volume in liters (0.100 L).

So, n=0.0100 M×0.100 L=0.00100 molesn = 0.0100 \text{ M} \times 0.100 \text{ L} = 0.00100 \text{ moles}

Step 2

Calculate moles of CO₂ required

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Answer

According to the balanced equation, 1 mole of Ca(OH)₂ reacts with 2 moles of CO₂. Thus, the moles of CO₂ required are:

nCO2=2×nCa(OH)2=2×0.00100=0.00200 molesn_{CO2} = 2 \times n_{Ca(OH)2} = 2 \times 0.00100 = 0.00200 \text{ moles}

Step 3

Calculate volume of CO₂ at STP

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Answer

At standard temperature and pressure (STP), 1 mole of a gas occupies 22.4 L. Therefore, we can find the volume of CO₂ that can be absorbed:

V=nCO2×22.4 L/mol=0.00200×22.4=0.0448 LV = n_{CO2} \times 22.4 \text{ L/mol} = 0.00200 \times 22.4 = 0.0448 \text{ L}

Converting this to mL: 0.0448 L×1000 mL/L=44.8 mL0.0448 \text{ L} \times 1000 \text{ mL/L} = 44.8 \text{ mL}

Step 4

Final Answer

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Answer

The maximum volume, in mL, at STP of CO₂ that could be absorbed by the solution is 44.8 mL.

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