Photo AI

A standard solution of potassium permanganate (KMnO₄) has a concentration of 0.0240 M - VCE - SSCE Chemistry - Question 9 - 2004 - Paper 1

Question icon

Question 9

A-standard-solution-of-potassium-permanganate-(KMnO₄)-has-a-concentration-of-0.0240-M-VCE-SSCE Chemistry-Question 9-2004-Paper 1.png

A standard solution of potassium permanganate (KMnO₄) has a concentration of 0.0240 M. It is titrated against a solution of iron (II) sulfate (FeSO₄). The equation ... show full transcript

Worked Solution & Example Answer:A standard solution of potassium permanganate (KMnO₄) has a concentration of 0.0240 M - VCE - SSCE Chemistry - Question 9 - 2004 - Paper 1

Step 1

Calculate Moles of KMnO₄ Used

96%

114 rated

Answer

To calculate the moles of KMnO₄ used in the titration, use the formula:

extmoles=extconcentrationimesextvolume ext{moles} = ext{concentration} imes ext{volume}

where concentration = 0.0240 M and volume = 15.60 mL (converted to L: 0.01560 L). So:

extmolesofKMnO4=0.0240imes0.01560=0.0003744extmoles ext{moles of KMnO₄} = 0.0240 imes 0.01560 = 0.0003744 ext{ moles}

Step 2

Use Stoichiometry to Find Moles of FeSO₄

99%

104 rated

Answer

From the balanced equation, the stoichiometry indicates:

1 ext{ mole of KMnO₄} $ \text{ reacts with } 5 ext{ moles of FeSO₄}

Using the moles of KMnO₄ calculated:

extmolesofFeSO4=5imes0.0003744=0.001872extmoles ext{moles of FeSO₄} = 5 imes 0.0003744 = 0.001872 ext{ moles}

Step 3

Calculate the Concentration of FeSO₄

96%

101 rated

Answer

The concentration of FeSO₄ can now be found using:

ext{concentration} = rac{ ext{moles}}{ ext{volume}}

with the volume of FeSO₄ being 20.00 mL (or 0.02000 L):

ext{concentration of FeSO₄} = rac{0.001872}{0.02000} = 0.0936 ext{ M}

Step 4

Final Answer Selection

98%

120 rated

Answer

The calculated concentration of FeSO₄ is 0.0936 M, which corresponds to option C.

Join the SSCE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;