The molecule with the structural formula shown below reacts with hydrogen bromide, HBr, to form C3H7Br - VCE - SSCE Chemistry - Question 18 - 2016 - Paper 1
Question 18
The molecule with the structural formula shown below reacts with hydrogen bromide, HBr, to form C3H7Br.
The number of different structural isomers theoretically pos... show full transcript
Worked Solution & Example Answer:The molecule with the structural formula shown below reacts with hydrogen bromide, HBr, to form C3H7Br - VCE - SSCE Chemistry - Question 18 - 2016 - Paper 1
Step 1
Identify the Parent Structure
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Answer
The given structural formula indicates that the molecule has 5 carbon atoms and 12 hydrogen atoms, making it a pentane derivative. This serves as the parent structure for the isomers.
Step 2
Understand the Reaction with HBr
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Answer
When the molecule reacts with hydrogen bromide (HBr), it introduces a bromine atom, replacing one of the hydrogen atoms in the alkane structure.
Step 3
Determine Possible Isomers
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Answer
To identify the structural isomers of C3H7Br, consider where the bromine atom can be attached and the arrangement of the remaining hydrogen atoms. Two distinct structural isomers can be formed: 1-bromopropane and 2-bromopropane.
Step 4
Conclusion
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Answer
Thus, the number of different structural isomers theoretically possible to be produced by this reaction is 2 (Answer B).
