An equilibrium mixture of four gases is represented by the following equation - VCE - SSCE Chemistry - Question 25 - 2021 - Paper 1
Question 25
An equilibrium mixture of four gases is represented by the following equation.
A(g) + 2B(g) ⇌ C(g) + D(g)
ΔH > 0
The graph below shows the rate of the forward and ... show full transcript
Worked Solution & Example Answer:An equilibrium mixture of four gases is represented by the following equation - VCE - SSCE Chemistry - Question 25 - 2021 - Paper 1
Step 1
A. Argon is added to the equilibrium mixture at time t1.
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Answer
This statement is unlikely to be true. Adding an inert gas like Argon does not change the concentrations of the reacting gases, thus it does not affect the equilibrium position.
Step 2
B. At time t1, reactants are removed from the equilibrium mixture.
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Answer
This would shift the equilibrium to the left (toward the reactants) according to Le Chatelier's principle, leading to an increase in the reactants and a potential decrease in products, which is inconsistent with the observed data.
Step 3
C. The amount of products is higher at time t2 compared to just before time t1.
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This is the most consistent option. If the amount of products is higher at time t2, it suggests that a dynamic equilibrium shift occurred which could be due to changes made at time t1.
Step 4
D. The change made at time t1 results in an increase in the equilibrium constant at time t2.
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The equilibrium constant only changes with temperature. If the temperature remains constant, this statement does not hold; thus, it is unlikely.