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Below are the half-equations for the lead-acid accumulator cell - VCE - SSCE Chemistry - Question 25 - 2023 - Paper 1

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Below are the half-equations for the lead-acid accumulator cell. The lead-acid accumulator cell can operate as an electrolytic cell. $$ ext{PbSO}_4(s) + ext{H}^+(... show full transcript

Worked Solution & Example Answer:Below are the half-equations for the lead-acid accumulator cell - VCE - SSCE Chemistry - Question 25 - 2023 - Paper 1

Step 1

Galvanic cell

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Answer

In a galvanic cell, the half-reaction for the lead-acid accumulator shows that the anode is where oxidation occurs. Here, at the anode, lead sulfate ( ext{PbSO}_4) is oxidized to lead dioxide ( ext{PbO}_2) while H+ ions are reduced at the cathode to form lead. Therefore,

Correct Statement: H+ ions react at the cathode.

Step 2

Electrolytic cell

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Answer

In an electrolytic cell, the process is driven externally. At the anode, oxidation occurs, where lead sulfate ( ext{PbSO}_4) is formed, and at the cathode, the reduction of H+ ions takes place. Hence,

Correct Statement: H+ ions react at the cathode.

Step 3

Final Selection

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Answer

Since the statements regarding both the galvanic and electrolytic process agree on the behavior of H+ ions reacting at the cathode, the correct option is C: H+ ions react at the cathode.

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