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Bioethanol, C2H5OH, is produced by the fermentation of glucose, C6H12O6, according to the following equation - VCE - SSCE Chemistry - Question 10 - 2018 - Paper 1

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Bioethanol, C2H5OH, is produced by the fermentation of glucose, C6H12O6, according to the following equation. C6H12O6(aq) → 2C2H5OH(aq) + 2CO2(g) The mass of C2H5O... show full transcript

Worked Solution & Example Answer:Bioethanol, C2H5OH, is produced by the fermentation of glucose, C6H12O6, according to the following equation - VCE - SSCE Chemistry - Question 10 - 2018 - Paper 1

Step 1

Calculate the moles of CO2 produced

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Answer

To find the moles of CO2 produced, we can use the equation:

n=mMn = \frac{m}{M}

where nn is the number of moles, mm is the mass (5.68 g), and MM is the molar mass of CO2 (approximately 44.01 g/mol).

Thus,

nCO2=5.68 g44.01 g/mol0.129 moln_{CO2} = \frac{5.68 \text{ g}}{44.01 \text{ g/mol}} \approx 0.129 \text{ mol}.

Step 2

Determine the moles of C2H5OH produced

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Answer

From the reaction equation:

C6H12O62C2H5OH+2CO2C6H12O6 \rightarrow 2C2H5OH + 2CO2

We see that 2 moles of C2H5OH are produced for every 2 moles of CO2. Therefore, the moles of C2H5OH produced are the same as the moles of CO2:

nC2H5OH=nCO20.129 moln_{C2H5OH} = n_{CO2} \approx 0.129 \text{ mol}.

Step 3

Calculate the mass of C2H5OH produced

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Answer

Using the equation again:

m=n×Mm = n \times M

where MM for C2H5OH is approximately 46.08 g/mol. Thus,

mC2H5OH=0.129 mol×46.08 g/mol5.94 gm_{C2H5OH} = 0.129 \text{ mol} \times 46.08 \text{ g/mol} \approx 5.94 \text{ g}.

Step 4

Choose the correct answer

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Answer

Based on the calculations, the mass of C2H5OH obtained is approximately 5.94 g. Therefore, the correct answer is D. 5.94 g.

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