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Two bottles, I and II, have the same volume and are at the same temperature - VCE - SSCE Chemistry - Question 17 - 2007 - Paper 1

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Two bottles, I and II, have the same volume and are at the same temperature. Bottle I contains 10 g of argon gas only. Bottle II contains 10 g of neon gas only. Comp... show full transcript

Worked Solution & Example Answer:Two bottles, I and II, have the same volume and are at the same temperature - VCE - SSCE Chemistry - Question 17 - 2007 - Paper 1

Step 1

number of atoms

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Answer

To determine the number of atoms, we first need to calculate the number of moles for each gas using the molar mass.

  • The molar mass of argon (Ar) is approximately 40 g/mol. Thus, for bottle I:

    extMolesofAr=10 g40 g/mol=0.25 moles ext{Moles of Ar} = \frac{10 \text{ g}}{40 \text{ g/mol}} = 0.25 \text{ moles}

  • The molar mass of neon (Ne) is approximately 20 g/mol. Thus, for bottle II:

    Moles of Ne=10 g20 g/mol=0.5 moles\text{Moles of Ne} = \frac{10 \text{ g}}{20 \text{ g/mol}} = 0.5 \text{ moles}

Since both bottles have the same volume and each mole of gas contains the same number of atoms according to Avogadro's principle, bottle II has approximately double the number of atoms compared to bottle I.

Step 2

pressure

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Answer

According to the ideal gas law, pressure is directly proportional to the number of moles of gas when volume and temperature are held constant. Since bottle II contains approximately double the moles of gas (0.5 moles of neon compared to 0.25 moles of argon), it will exert a higher pressure:

  • Therefore, the pressure in bottle II would be higher than in bottle I.

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