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A sample of the anticancer drug Taxol®, C₁₄H₁₁N₃O₄, contains 0.157 g of carbon - VCE - SSCE Chemistry - Question 15 - 2012 - Paper 1

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A sample of the anticancer drug Taxol®, C₁₄H₁₁N₃O₄, contains 0.157 g of carbon. The mass, in grams, of oxygen in the sample is.

Worked Solution & Example Answer:A sample of the anticancer drug Taxol®, C₁₄H₁₁N₃O₄, contains 0.157 g of carbon - VCE - SSCE Chemistry - Question 15 - 2012 - Paper 1

Step 1

Calculate the Molar Mass of Taxol®

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Answer

To find the mass of oxygen in the sample, first calculate the molar mass of the compound Taxol® (C₁₄H₁₁N₃O₄).

The molar mass can be calculated as follows:

  • Carbon (C): 12.01 g/mol × 14 = 168.14 g/mol
  • Hydrogen (H): 1.01 g/mol × 11 = 11.11 g/mol
  • Nitrogen (N): 14.01 g/mol × 3 = 42.03 g/mol
  • Oxygen (O): 16.00 g/mol × 4 = 64.00 g/mol

Total Molar Mass of Taxol®: M=168.14+11.11+42.03+64.00=285.28extg/molM = 168.14 + 11.11 + 42.03 + 64.00 = 285.28 ext{ g/mol}

Step 2

Determine the Number of Moles of Carbon

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Answer

Calculate the number of moles of carbon in the sample using the mass of carbon:

n_{C} = rac{mass}{molar ext{ }mass} = rac{0.157 ext{ g}}{12.01 ext{ g/mol}} = 0.0131 ext{ mol}

Step 3

Calculate the Moles of Oxygen

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Answer

Using the molar ratio from the formula C₁₄H₁₁N₃O₄, we can find the moles of oxygen (O). There are 4 moles of oxygen for every mole of Taxol®.

Since there are 14 carbons in the compound, we can scale it: n_{O} = n_{C} imes rac{4}{14} = 0.0131 imes rac{4}{14} = 0.00374 ext{ mol}

Step 4

Convert Moles of Oxygen to Grams

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Answer

Now, convert the moles of oxygen to grams:

massO=nOimesmolarextmassO=0.00374extmolimes16.00extg/mol=0.05984extgmass_{O} = n_{O} imes molar ext{ }mass_{O} = 0.00374 ext{ mol} imes 16.00 ext{ g/mol} = 0.05984 ext{ g}

Step 5

Final Result

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Answer

Since 0.05984 g does not perfectly match any of the provided options, we round this result. The closest value is 0.0624 g, which corresponds to option B.

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