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Carbon monoxide and hydrogen can be produced from the reaction of methane with steam according to the equation $$CH_4(g) + H_2O(g) ⇌ CO(g) + 3H_2(g); \, ΔH = +206 \, kJ \, mol^{-1}$$ Some methane and steam are placed in a closed container and allowed to react at a fixed temperature - VCE - SSCE Chemistry - Question 1 - 2007 - Paper 1

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Question 1

Carbon-monoxide-and-hydrogen-can-be-produced-from-the-reaction-of-methane-with-steam-according-to-the-equation--$$CH_4(g)-+-H_2O(g)-⇌-CO(g)-+-3H_2(g);-\,-ΔH-=-+206-\,-kJ-\,-mol^{-1}$$--Some-methane-and-steam-are-placed-in-a-closed-container-and-allowed-to-react-at-a-fixed-temperature-VCE-SSCE Chemistry-Question 1-2007-Paper 1.png

Carbon monoxide and hydrogen can be produced from the reaction of methane with steam according to the equation $$CH_4(g) + H_2O(g) ⇌ CO(g) + 3H_2(g); \, ΔH = +206 \... show full transcript

Worked Solution & Example Answer:Carbon monoxide and hydrogen can be produced from the reaction of methane with steam according to the equation $$CH_4(g) + H_2O(g) ⇌ CO(g) + 3H_2(g); \, ΔH = +206 \, kJ \, mol^{-1}$$ Some methane and steam are placed in a closed container and allowed to react at a fixed temperature - VCE - SSCE Chemistry - Question 1 - 2007 - Paper 1

Step 1

a. i. On the graph above, draw a line to show the change in concentration of hydrogen gas as the reaction progresses. Label this line.

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Answer

To indicate the change in concentration of hydrogen gas (H₂) over time, I will draw a line starting at zero concentration and increasing as the reaction progresses, eventually leveling off as equilibrium is approached. This line will be labeled as H₂.

Step 2

a. ii. On the graph above, draw a line to show the formation of carbon monoxide would differ over time in the presence of a catalyst. Label this line.

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Answer

In the presence of a catalyst, the reaction rate for the formation of carbon monoxide (CO) would increase. Therefore, I will draw a steeper line from the starting point to indicate a faster increase in concentration compared to the line without a catalyst. This will be labeled as CO with catalyst.

Step 3

b. What does the above information indicate about the magnitude of the equilibrium constant K₁ compared with the magnitude of the equilibrium constant K₂?

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Answer

The information suggests that the equilibrium constant K₂ for the reaction involving carbon monoxide is likely to be smaller than K₁. This is because carbon monoxide competes with oxygen for binding to haemoglobin, indicating that the formation of carbon monoxide-haemoglobin complex is favored under these conditions, thus reducing the concentration of haemoglobin available for binding with oxygen.

Step 4

c. Indicate whether the following statements about rates in the collision theory model are true or false.

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Answer

StatementTrueFalse
i. Endothermic reactions are always slower than exothermic reactions.
ii. All particles have the same kinetic energy at a fixed temperature.
iii. Reactant particles collide in order to react.
iv. The rate of reaction at a constant temperature increases as the surface area of the reactants increases.
v. Temperature increases the fraction of collisions with energy.

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