The molar heat of combustion of glucose, C₆H₁₂O₆, in the cellular respiration equation is 2805 kJ mol⁻¹ at standard laboratory conditions (SLC) - VCE - SSCE Chemistry - Question 15 - 2022 - Paper 1
Question 15
The molar heat of combustion of glucose, C₆H₁₂O₆, in the cellular respiration equation is 2805 kJ mol⁻¹ at standard laboratory conditions (SLC).
Which one of the fo... show full transcript
Worked Solution & Example Answer:The molar heat of combustion of glucose, C₆H₁₂O₆, in the cellular respiration equation is 2805 kJ mol⁻¹ at standard laboratory conditions (SLC) - VCE - SSCE Chemistry - Question 15 - 2022 - Paper 1
Step 1
A. Cellular respiration is an endothermic reaction.
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Answer
This statement is incorrect. Cellular respiration is an exothermic process as it releases energy.
Step 2
B. The products of cellular respiration are carbon and carbon dioxide.
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This statement is partially true, but it is misleading. The primary products of cellular respiration are carbon dioxide and water.
Step 3
C. Cellular respiration is a redox reaction because C₆H₁₂O₆ accepts electrons from oxygen.
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Answer
This is incorrect. In cellular respiration, glucose (C₆H₁₂O₆) acts as the reducing agent by donating electrons, while oxygen acts as the oxidizing agent by accepting electrons.
Step 4
D. When one mole of oxygen is consumed in the reaction, 467.5 kJ of energy is released.
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Answer
This statement is correct in the context provided. Energy is indeed released during the oxidation of glucose in cellular respiration, but the precise amount would depend on the entire balanced reaction.
