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When two mole of an organic compound is burnt in oxygen, eight mole of carbon dioxide gas is formed - VCE - SSCE Chemistry - Question 15 - 2002 - Paper 1

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When two mole of an organic compound is burnt in oxygen, eight mole of carbon dioxide gas is formed. In a second test, when a few drops of bromine are added to the c... show full transcript

Worked Solution & Example Answer:When two mole of an organic compound is burnt in oxygen, eight mole of carbon dioxide gas is formed - VCE - SSCE Chemistry - Question 15 - 2002 - Paper 1

Step 1

Identify the chemical reaction

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Answer

From the burning of the organic compound in oxygen, we know that 2 moles of the compound produce 8 moles of carbon dioxide. The general equation for combustion can be expressed as:

ightarrow CO_2 + H_2O$$ This tells us that the ratio of carbon in the compound to carbon dioxide produced is a crucial component.

Step 2

Calculate the carbon content

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Since 8 moles of CO₂ are produced, this implies there are 8 moles of carbon in 2 moles of the compound. Thus, for 1 mole of the compound, there must be 4 moles of carbon:

rac{8 ext{ moles CO}_2}{2 ext{ moles compound}} = 4 ext{ moles C per mole of compound}

Step 3

Determine hydrogen content

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Next, we relate the number of hydrogen atoms to the general formula. For alkanes, the general formula is CₙH₍₂ₙ₊₂₎. Given that there are 4 carbons in the compound:

  • For alkanes: A molecule with 4 carbon atoms would have:

extH=2(4)+2=10extH ext{H} = 2(4) + 2 = 10 ext{ H}

Step 4

Evaluate the options

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The formula that corresponds with our findings (C₄H₁₀) does not directly match any options, but we note the closest related formula provided in the choices. The formula C₈H₁₈ indicates a saturated alkane with 8 carbon atoms, suggesting that it could satisfy both conditions given that the compound could also be a higher alkane. Thus, the best choice is:

Answer: D. C₈H₁₈

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