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The reaction between 2-bromo-2-methylpropane and hydroxide ions occurs in two steps - VCE - SSCE Chemistry - Question 2 - 2012 - Paper 1

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The reaction between 2-bromo-2-methylpropane and hydroxide ions occurs in two steps. step 1: (CH₃)₃CBr(aq) → (CH₃)₃C⁺ + Br⁻(aq) step 2: (CH₃)₃C⁺(aq) + OH... show full transcript

Worked Solution & Example Answer:The reaction between 2-bromo-2-methylpropane and hydroxide ions occurs in two steps - VCE - SSCE Chemistry - Question 2 - 2012 - Paper 1

Step 1

a. Write an equation that represents the overall reaction between 2-bromo-2-methylpropane and hydroxide ions.

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Answer

The overall reaction can be represented as:

(CH3)3CBr(aq)+OH(aq)(CH3)3COH(aq)+Br(aq)(CH_3)_3CBr(aq) + OH^-(aq) → (CH_3)_3COH(aq) + Br^-(aq)

Step 2

b. i. Which step involves an endothermic reaction? Provide a reason for your answer.

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Answer

Step 1 involves an endothermic reaction because the energy required to form the carbocation intermediate, (CH3)3C+(CH_3)_3C^+, is higher than that of the reactant (CH3)3CBr(CH_3)_3CBr.

Step 3

b. ii. Which step is slower? Justify your answer.

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Answer

Step 1 is slower due to the formation of the carbocation intermediate, which requires overcoming a higher activation energy barrier compared to the second step, where the nucleophilic attack occurs.

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