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The trisaccharide formed from the reaction of three glucose (C₆H₁₂O₆) molecules has the formula: A - VCE - SSCE Chemistry - Question 1 - 2005 - Paper 1
Question 1
The trisaccharide formed from the reaction of three glucose (C₆H₁₂O₆) molecules has the formula: A. C₁₈H₃₈O₁₈ B. C₁₈H₃₄O₁₇ C. C₁₈H₃₃O₁₆ D. C₁₈H₃₄O₁₅
Worked Solution & Example Answer:The trisaccharide formed from the reaction of three glucose (C₆H₁₂O₆) molecules has the formula: A - VCE - SSCE Chemistry - Question 1 - 2005 - Paper 1
Step 1
Determine the formula for the trisaccharide
Answer
To calculate the molecular formula of the trisaccharide, consider that three glucose molecules (C₆H₁₂O₆) undergo a condensation reaction. Each reaction releases a water molecule (H₂O).
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Start with three glucose molecules:
- C₆H₁₂O₆ × 3 = C₁₈H₃₆O₁₈
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Since two water molecules are formed during the condensation (one between each pair of glucose), subtract the components of two water molecules:
- Water (H₂O) contains 2 H and 1 O. For two water molecules, we need to subtract 4 H and 2 O:
- C₁₈H₃₆O₁₈ - 4H - 2O results in:
- C₁₈H₃₂O₁₆
After calculating, the formula for the trisaccharide formed from three glucose is C₁₈H₃₂O₁₆. Therefore, the answer corresponds to option C.