Consider the following three compounds which contain complex ions that involve iron
I [Fe(NH₃)₆]Cl₃
II K₃[FeCl₆]
III K₃[FeCl₄]
The oxidation state of the iron in each of these compounds is
A - VCE - SSCE Chemistry - Question 19 - 2005 - Paper 1
Question 19
Consider the following three compounds which contain complex ions that involve iron
I [Fe(NH₃)₆]Cl₃
II K₃[FeCl₆]
III K₃[FeCl₄]
The oxidation state of the iron i... show full transcript
Worked Solution & Example Answer:Consider the following three compounds which contain complex ions that involve iron
I [Fe(NH₃)₆]Cl₃
II K₃[FeCl₆]
III K₃[FeCl₄]
The oxidation state of the iron in each of these compounds is
A - VCE - SSCE Chemistry - Question 19 - 2005 - Paper 1
Step 1
I [Fe(NH₃)₆]Cl₃
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Answer
In the compound [Fe(NH₃)₆]Cl₃, NH₃ is a neutral ligand, which does not contribute to the oxidation state. The three chloride ions (Cl-) contribute -3 total. Hence, the oxidation state of iron (Fe) must be +3 to balance this:
total oxidation state: +3 + 3(-1) = 0
Thus, the oxidation state of iron in I is +3.
Step 2
II K₃[FeCl₆]
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Answer
In K₃[FeCl₆], the compound overall must remain neutral, and potassium (K) has a +1 charge. With three potassium ions, this gives +3 total. The six chloride ions (Cl-) bring a total charge of -6. Therefore, the iron must have an oxidation state of:
total oxidation state: x + 6(-1) + 3(+1) = 0
⇒ x - 6 + 3 = 0
⇒ x = +3
Thus, the oxidation state of iron in II is +3.
Step 3
III K₃[FeCl₄]
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Answer
In K₃[FeCl₄], similarly to the previous compound, the three potassium ions give a +3 charge, while the four chloride ions contribute -4 total:
total oxidation state: x + 4(-1) + 3(+1) = 0
⇒ x - 4 + 3 = 0
⇒ x = +1