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In a fuel cell based on the oxidation of methane, the equation for the anode half reaction is CH₄(g) + 2H₂O(l) → CO₂(g) + 8H⁺(aq) + 8e⁻ The corresponding equation for the half reaction at the cathode is A - VCE - SSCE Chemistry - Question 5 - 2004 - Paper 1

Question 5

In-a-fuel-cell-based-on-the-oxidation-of-methane,-the-equation-for-the-anode-half-reaction-is--CH₄(g)-+-2H₂O(l)-→-CO₂(g)-+-8H⁺(aq)-+-8e⁻--The-corresponding-equation-for-the-half-reaction-at-the-cathode-is-A-VCE-SSCE Chemistry-Question 5-2004-Paper 1.png

In a fuel cell based on the oxidation of methane, the equation for the anode half reaction is CH₄(g) + 2H₂O(l) → CO₂(g) + 8H⁺(aq) + 8e⁻ The corresponding equation ... show full transcript

Worked Solution & Example Answer:In a fuel cell based on the oxidation of methane, the equation for the anode half reaction is CH₄(g) + 2H₂O(l) → CO₂(g) + 8H⁺(aq) + 8e⁻ The corresponding equation for the half reaction at the cathode is A - VCE - SSCE Chemistry - Question 5 - 2004 - Paper 1

Step 1

Identify the anode half reaction

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Answer

The given anode half reaction is:

$CH₄(g) + 2H₂O(l) → CO₂(g) + 8H⁺(aq) + 8e⁻$

This reaction represents the oxidation of methane, where it is converted to carbon dioxide, protons, and electrons.

Step 2

Determine the corresponding cathode reaction

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Answer

In a fuel cell, the cathode reaction typically involves the reduction of protons in the presence of oxygen. Among the given options for the cathode reaction, the correct one is:

D. $4H⁺(aq) + O₂(g) → 2H₂O(l)$

This equation shows the reduction of protons and oxygen to produce water, which corresponds correctly to the overall redox process in a fuel cell.

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