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A vanadium redox battery is used to store electrical energy generated at a wind farm in Tasmania - VCE - SSCE Chemistry - Question 5 - 2009 - Paper 1

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A vanadium redox battery is used to store electrical energy generated at a wind farm in Tasmania. The battery supplies electricity to the power grid as required thro... show full transcript

Worked Solution & Example Answer:A vanadium redox battery is used to store electrical energy generated at a wind farm in Tasmania - VCE - SSCE Chemistry - Question 5 - 2009 - Paper 1

Step 1

a. State the polarity of each electrode as the battery is discharged.

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Answer

Electrode A is positive (+) and Electrode B is negative (−). As the battery discharges, Electrode A becomes the anode (where oxidation occurs), and Electrode B becomes the cathode (where reduction occurs).

Step 2

b. Circle the vanadium-containing ion that would have the highest concentration at the anode when the cell is fully charged.

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The vanadium-containing ion with the highest concentration at the anode when the cell is fully charged is (\text{VO}_2^{+}). At full charge, this ion accumulates as the oxidized form of vanadium.

Step 3

c. Write a balanced overall equation for the reaction that occurs when the cell is being recharged.

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The balanced overall equation during recharging is:

VO2+(aq)+V3+(aq)+2H+(aq)VO2+(aq)+V2+(aq)+H2O(l)\text{VO}^{2+}(aq) + \text{V}^{3+}(aq) + 2H^{+}(aq) \rightarrow \text{VO}_2^{+}(aq) + \text{V}^{2+}(aq) + H_2O(l)

Step 4

d. Compare the vanadium redox cell to a fuel cell by describing one major way in which they differ.

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One major difference is that a vanadium redox cell is rechargeable, while many fuel cells are not. Fuel cells typically consume fuel continuously and require a constant supply of reactants, whereas vanadium redox cells can be recharged and reused.

Step 5

e. Write a balanced overall equation to show why iron would be an unsuitable material to use as electrode B in the vanadium redox cell.

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Using iron as electrode B would lead to the following reaction:

Fe3+(aq)+3eFe(s)\text{Fe}^{3+}(aq) + 3e^{-} \rightarrow \text{Fe}(s)

As iron can react with the electrolyte, it would corrode and degrade, making it unsuitable for use in this cell.

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