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Sodium is an essential element in our diets - VCE - SSCE Chemistry - Question 1 - 2003 - Paper 1

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Sodium is an essential element in our diets. However, the amount of sodium present in some foods is often much higher than levels recommended for health. A sauce was... show full transcript

Worked Solution & Example Answer:Sodium is an essential element in our diets - VCE - SSCE Chemistry - Question 1 - 2003 - Paper 1

Step 1

a. Use the above data for the Na⁺(aq) standards to plot a calibration line on the graph below.

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Answer

To plot the calibration line, take the absorbance values from the standard solutions and plot them against their corresponding sodium concentrations. Ensure to draw a best fit line through the plotted points.

Step 2

b. Use your calibration graph to determine the sodium ion concentration in the diluted sample of the sauce and in the original sauce.

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Answer

Using the calibration graph, find the absorbance value of the diluted sauce (0.185) on the y-axis, and draw a horizontal line to intersect the calibration curve. Read the corresponding concentration from the x-axis. For the original sauce, consider the dilution factor (1:40), thus multiply the value obtained from the graph by 40.

Step 3

c. i. What important assumption must you make in order to calculate the NaCl content of the sauce from the Na⁺ concentration?

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You must assume that all the sodium present in the sample comes exclusively from NaCl (sodium chloride), and there are no other sodium sources present.

Step 4

c. ii. Calculate the concentration of NaCl in the original (undiluted) sauce in g L⁻¹.

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Answer

First, determine the concentration of Na⁺ in the original sauce. If the concentration of Na⁺ is calculated to be 372 mg L⁻¹, then convert this to NaCl concentration:

m(NaCl)=m(Na+)×MW(NaCl)MW(Na)\text{m(NaCl)} = m(Na^+) \times \frac{MW(NaCl)}{MW(Na)} m(NaCl)=372 mg L1×58.4422.991.36 g L1\text{m(NaCl)} = 372 \text{ mg L}^{-1} \times \frac{58.44}{22.99} \approx 1.36 \text{ g L}^{-1}

Step 5

c. iii. What percentage of a maximum daily recommended intake would be consumed by a person who eats 10 mL of the original (undiluted) sauce?

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Answer

Calculate the amount of NaCl consumed:

m(NaCl) consumed=10 mL×1.36 g L1=0.0136 g\text{m(NaCl) consumed} = 10 \text{ mL} \times 1.36 \text{ g L}^{-1} = 0.0136 \text{ g}

The percentage of the maximum daily intake:

Percentage=(0.0136 g2.5 g)×1000.54%\text{Percentage} = \left(\frac{0.0136 \text{ g}}{2.5 \text{ g}}\right) \times 100 \approx 0.54\%

Step 6

d. Why is it that atomic absorption spectroscopy will measure only the sodium ion concentration in your sample and not the concentration of some other substance or substances as well?

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Answer

Atomic absorption spectroscopy specifically measures the absorption of light by free ions in a gaseous state. Each ion has a specific wavelength that it absorbs light at, allowing it to be distinguished from other substances present in the sample.

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