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An organic compound is known to contain only carbon, hydrogen and oxygen - VCE - SSCE Chemistry - Question 11 - 2005 - Paper 1

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An organic compound is known to contain only carbon, hydrogen and oxygen. The compound contains, by mass, 39.1% of carbon and 8.7% of hydrogen. The number of carbon ... show full transcript

Worked Solution & Example Answer:An organic compound is known to contain only carbon, hydrogen and oxygen - VCE - SSCE Chemistry - Question 11 - 2005 - Paper 1

Step 1

Calculate Moles of Carbon

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Answer

To find the moles of carbon, we use the formula:

ext{Moles of Carbon} = rac{ ext{mass percentage of Carbon}}{ ext{molar mass of Carbon}}

Given:

  • Mass percentage of Carbon = 39.1%
  • Molar mass of Carbon = 12.01 g/mol

Calculating the moles:

ext{Moles of Carbon} = rac{39.1}{12.01} \approx 3.25 ext{ moles}

Step 2

Calculate Moles of Hydrogen

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Answer

Next, we calculate the moles of hydrogen using a similar method:

ext{Moles of Hydrogen} = rac{ ext{mass percentage of Hydrogen}}{ ext{molar mass of Hydrogen}}

Given:

  • Mass percentage of Hydrogen = 8.7%
  • Molar mass of Hydrogen = 1.008 g/mol

Calculating the moles:

ext{Moles of Hydrogen} = rac{8.7}{1.008} \approx 8.63 ext{ moles}

Step 3

Calculate Moles of Oxygen

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Now we assume the remaining mass is oxygen:

  • Mass percentage of Oxygen = 100% - (39.1% + 8.7%) = 52.2%

Calculating moles of oxygen:

ext{Moles of Oxygen} = rac{52.2}{16.00} \approx 3.26 ext{ moles}

Step 4

Determine the Simplest Ratio

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We now have the moles of each element:

  • Moles of Carbon = 3.25 moles
  • Moles of Hydrogen = 8.63 moles
  • Moles of Oxygen = 3.26 moles

To find the simplest whole number ratio, we divide each by the smallest value (3.25):

ext{Ratio of Carbon} = \frac{3.25}{3.25} = 1\ ext{Ratio of Hydrogen} = \frac{8.63}{3.25} \approx 2.65 \ ext{Ratio of Oxygen} = \frac{3.26}{3.25} \approx 1\

To approximate to whole numbers, we can round Hydrogen to 3. Thus, the empirical formula is C1H3O1.

Step 5

Empirical Formula Conclusion

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Answer

The number of carbon atoms in the empirical formula is therefore:

  • C1H3O1 implies there is 1 carbon atom per empirical unit.

The answer is thus: A. 1

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