A representation of a section of a polymer chain, that has been produced from two different monomers, is given below - VCE - SSCE Chemistry - Question 19 - 2005 - Paper 1

To identify the two monomers that produce the given polymer chain, we can break down the structure of the chain into its repeating units. We observe that the polymer consists of alternating segments of –CF2– and –CF– than indicate a vinyl monomer with either CF2 or CF3 side groups. Examining the options:

1. Option A: CH2=CF2 and CF2=CFCF3 - This can produce alternating CF2 and CF due to the presence of double bonds at the ends. This is a feasible structure for the repeating unit.

2. Option B: CF2=CF2 and CF2=CFCF3 - This might not explain the observed structures properly as both components would not lead to the required variation in the chain.

3. Option C: CH2=CF2 and CH2=CF3 - The second monomer cannot produce the observed chain structure with alternating CF and CF2.

4. Option D: CF2=CF2 and CH2=CFCF3 - Similar to Option B, the polymer structure from these two cannot maintain the observed pattern.

Upon evaluating the options, the correct answer is A: CH2=CF2 and CF2=CFCF3.