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Quadratic Equations Guide Simplified Revision Notes

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Quadratic Equations Guide

A quadratic equation is a polynomial equation of the second degree, formulated as:

ax2+bx+c=0ax^2 + bx + c = 0

  • aa: leading coefficient
  • bb: linear coefficient
  • cc: constant term

The Quadratic Formula

The quadratic formula is used to determine the values of xx:

x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

  • Discriminant Δ=b24ac\Delta = b^2 - 4ac:
    • Defines the number and nature of roots.
infoNote

Discriminant Δ\Delta:

  • Positive Δ\Delta: Two distinct solutions.
  • Zero Δ\Delta: One repeated solution.
  • Negative Δ\Delta: No real solutions.

Derivation of the Quadratic Formula

  1. Begin with: ax2+bx+c=0ax^2 + bx + c = 0.
  2. Rearrange to: ax2+bx=cax^2 + bx = -c.
  3. Normalise: x2+bax=cax^2 + \frac{b}{a}x = -\frac{c}{a}.
  4. Complete the square:
    • Add and subtract (b2a)2\left(\frac{b}{2a}\right)^2: x2+bax+(b2a)2=(b2a)2cax^2 + \frac{b}{a}x + \left(\frac{b}{2a}\right)^2 = \left(\frac{b}{2a}\right)^2 - \frac{c}{a}
  5. Simplify: (x+b2a)2=b24ac4a2\left(x + \frac{b}{2a}\right)^2 = \frac{b^2 - 4ac}{4a^2}
  6. Solve for xx: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Solving Quadratic Equations: Methods

Completing the Square

This method transforms quadratic equations into the form (xh)2=k(x - h)^2 = k.

Step-by-Step Transformation Process:

  1. Begin with ax2+bx+c=0ax^2 + bx + c = 0.
  2. Normalise: Divide by aa if a1a \neq 1.
  3. Complete the square on x2+baxx^2 + \frac{b}{a}x.
  4. Add and subtract (b2a)2\left(\frac{b}{2a}\right)^2.
  5. Rewrite in the form (xh)2=k(x - h)^2 = k.

Example:

  • Equation: x2+6x+5=0x^2 + 6x + 5 = 0.
  • Process:
    • x2+6x=5x^2 + 6x = -5.
    • Add and subtract 32=93^2 = 9:
      • x2+6x+9=5+9x^2 + 6x + 9 = -5 + 9
      • (x+3)2=4(x + 3)^2 = 4
      • x+3=±2x + 3 = \pm 2
      • x=3±2x = -3 \pm 2
      • x=1x = -1 or x=5x = -5

Vertex and Intercepts

Vertex: The point where the parabola changes direction.

Axis of Symmetry: A vertical line through the vertex that divides the parabola equally.

Finding Vertex:

  • Vertex Formula: x=b2ax = -\frac{b}{2a}

Example:

  • Equation: y=x22x+1y = x^2 - 2x + 1.
  • For vertex, find x=22(1)=1x = -\frac{-2}{2(1)} = 1
  • Substitute to find y=122(1)+1=0y = 1^2 - 2(1) + 1 = 0
  • Vertex at (1,0)(1, 0).

Graph Interpretation

Standard vs. Vertex Form:

  • Standard Form: y=ax2+bx+cy = ax^2 + bx + c
  • Vertex Form: y=a(xh)2+ky = a(x-h)^2 + k

Conversion Example:

  • From: y=2x2+4x+1y = 2x^2 + 4x + 1
  • To:
    • y=2(x2+2x)+1y = 2(x^2 + 2x) + 1
    • y=2(x2+2x+11)+1y = 2(x^2 + 2x + 1 - 1) + 1
    • y=2(x+1)22+1y = 2(x+1)^2 - 2 + 1
    • y=2(x+1)21y = 2(x+1)^2 - 1

Effects of coefficients on a parabolic graph

Discriminant

Determining Nature of Roots:

  • Positive Δ\Delta: Two unique roots.
  • Zero Δ\Delta: One repeated root.
  • Negative Δ\Delta: Complex roots.

Discriminant impact on graphs

Common Errors Section

  • Arithmetic Mistakes: Misuse of signs.
  • Parenthesis Misplacement: Leads to incorrect simplifications.

Ensure equations remain balanced and meticulously verify every step.

Practical Applications

The quadratic formula is crucial in fields like physics and economics.

  • Projectile Motion: Identifies when a projectile will land.
  • Economics: Examines break-even points in profit assessments.

Exam Tips:

  • Evaluate the discriminant before solving.
  • Utilise graphing calculators to confirm solutions.
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