Quadratic Expressions and Identities Simplified Revision Notes for SSCE HSC Mathematics Advanced
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Learn about Identity of two quadratic expressions for your SSCE Mathematics Advanced Exam. This Revision Note includes a summary of Identity of two quadratic expressions for easy recall in your Mathematics Advanced exam
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Quadratic Expressions and Identities
Introduction to Identities
Definition and Distinction
Algebraic Identity: An algebraic identity is an equation valid for all values of the variables involved.
Example: The identity (x+y)2=x2+2xy+y2 holds true universally for any x and y.
Conditional Equation: An equation only true for particular values of the variables.
Example: The equation x2=4 holds when x=2 or x=−2.
Applications in Problem-solving:
Simplify expressions effectively.
Facilitate the resolution of complex algebraic problems.
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Algebraic Identity: Valid for all variable values.
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Conditional Equation: Valid only for specific values.
Common Algebraic Identities
Square of a Binomial:
Formula: (a+b)2=a2+2ab+b2
Interactive Exercise: Expand (2x+3)2 and verify your work.
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Square of a Binomial: Master this formula to expand expressions efficiently.
Difference of Squares:
Formula: a2−b2=(a+b)(a−b)
Example: Simplify x2−9 as (x+3)(x−3).
infoNote
Recall, using the difference of squares is an effective strategy for simplifying expressions such as x2−b2.
Conceptual Clarification
Identity vs Conditional Equation:
Identities are applicable universally.
Conditional equations are limited to specific variable values.
Diagram Reference:
Grasping identities is vital for successful algebraic simplification.
Importance of Identities
Simplification and Problem-solving:
Diminish the complexity of expressions.
Provide foundational support for advanced algebraic processes.
Essential tools for efficiently solving diverse examination problems.
Quadratic Expressions
Definition and Form
Quadratic Expression: A quadratic expression is any expression of the form ax2+bx+c, where a, b, and c are constants, with a=0.
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Quadratic Expression: The form ax2+bx+c is described as a quadratic expression with constants a, b, and c such that a=0.
Techniques for Expanding and Simplifying
Distributive Property: Employ the distributive property to multiply every term in one binomial by each term in the other.
Step-by-step Examples:
Example Expansion 1:
Expand (x+2)(x+3) using the distributive property.
Multiply: x(x+3)+2(x+3).
Result: x2+5x+6.
Example Expansion 2:
Expand (2x+1)(x−5).
Multiply: 2x(x−5)+1(x−5).
Result: 2x2−9x−5.
Diagram Explanation:
Common Errors in Expansion
Common Mistakes:
Sign Errors: Mismanagement of positive or negative signs.
Incorrect Multiplication: Failure to multiply each portion correctly.
infoNote
Tips to avoid errors: Carefully check each multiplication process and stay alert for sign changes. Always review each step.
Practice Problems
Problem 1: Expand and simplify 3(x+4)(x+2).
Problem 2: Simplify (x−1)2−(x+5).
Advanced Problem: Expand and simplify (x−3)(2x+4)(x−2).
To verify whether quadratic expressions are identical, compare the equality of their corresponding coefficients and structure.
Identifying identical expressions: Verify the correspondence of coefficients.
Quadratic Expression: Presented as ax2+bx+c.
a,b,c: Coefficients.
Methods for Identifying Identical Quadratic Expressions
Comparison by Expanding and Simplifying
Expand: Carefully multiply out any brackets (e.g., (x+2)(x+3) transforms into x2+5x+6). Review expanded steps for accuracy.
Simplify: Consolidate like terms to reach the simplest form.
Compare: Confirm whether the simplified forms are identical.
Substitution Method
Substitute: Select simple values for x, such as 0, 1, 2.
Evaluate: Matching outcomes indicate identity for chosen values, but further testing is required for general validity.
Crucial Point: Multiple trials imply identity verification, with algebraic confirmation.
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Limitations: Why might substitution be insufficient? Ensure thorough evaluation of various values.
Flowchart
Examples
Example 1:
Compare x2+3x+2 and (x+1)(x+2).
Expand: (x+1)(x+2)=x2+2x+x+2=x2+3x+2.
Simplified forms indicate the expressions are equivalent.
Example 2:
Compare x2+5x+6 and (x+2)(x+3).
Evaluate for x=0,1.
Note: Consistent results suggest identity but ensure variability with further checks.
Common Misconceptions and Solutions
Misconception 1: Ignoring zero coefficients.
Solution: Explicitly verify every term for complete accuracy.
Misconception 2: Misaligned terms during comparison.
Solution: Reassess alignment by polynomial degree carefully.
Equating Coefficients
Identical Expressions: Quadratic expressions that share identical coefficients for each term.
infoNote
In identical expressions, equate each coefficient to ensure equivalence:
Expression 1: ax2+bx+c
Expression 2: dx2+ex+f
Equate: a=d, b=e, c=f.
This technique aids in validating expression equality.
Solving Systems of Equations
Substitution Method
Steps to solve:
Recognise system: a+b=5, a−b=1
Substitute: b=5−a in a−b=1
Result: a−(5−a)=1.
Solution: Calculate a=3, then b=2.
Elimination Method
Key steps:
Solve the system: 2a+3b=8, 4a−b=2
Multiply and add: Eliminate b through 12a−3b=6
Result: Solve for a and substitute for b
Exam Tips
Diligently review and compare each step during expansion and simplification.
Validate expression identity via both substitution and coefficient comparison methods.
Double-check calculations to prevent errors and ensure logical results.
Master solving systems of equations to identify unknown coefficients effectively.
Practice Problems
Problem 1: Determine if x2+4x+4 and (x+2)2 are identical.
Solution: Confirm by expansion: (x+2)2=x2+4x+4. The forms are equivalent.
Problem 2: Confirm if 2x2+3x+1 corresponds with (x+1)(2x+1) using substitutions.
Solution: Evaluate at various x-values; consistent outcomes verify identity.
Problem 3: Show that x2+6x+9 coincides with (x+3)2 using both methods.
Solution: Consistent expansion and substitution results affirm identity.
Practical Scenarios
Scenario 1: Optimise field area using 60m of fencing.
Scenario 2: Determine projectile's peak height duration at 15 m/s.
Scenario 3: Maximise profit for the equation P(x)=−6x2+120x−400.
Graphical Interpretation
Analyse parabolas by identifying vertex and axis of symmetry.
Apply to predict outcomes and determine problem-solving strategies effectively.
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