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Area Calculation in Integrals Simplified Revision Notes

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Area Calculation in Integrals

In advanced calculus, comprehending how to calculate areas under curves is crucial. This guide delves into key concepts, techniques, and real-world applications involving areas in integral calculus.

Key Term: Area under a Curve

infoNote

Area under a Curve: Denotes the total space between a curve and the x-axis, a vital concept in calculus.

  • Importance: A core principle in integral calculus, utilised to compute cumulative values over intervals.
  • Applications: Employed in various fields, such as physics (displacement) and economics (cost analysis).

Definite Integrals and Their Context

Real-world Applications

  • Engineering: Determine plot areas for construction.
  • Physics: Calculate total distance using velocity functions.
  • Economics: Assess consumer surplus beneath demand curves.

Understanding these applications underscores the importance of integrals.

Definite Integral Notation

A definite integral, symbolised as abf(x)dx\int_a^b f(x) \, dx, encompasses:

  • \int: The integration process.
  • a,ba, b: The limits of integration.
  • f(x)f(x): The function to integrate.
  • dxdx: Specifies integration concerning xx.
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Definite Integral Definition

  • Notation: abf(x)dx\int_a^b f(x) \, dx
  • Perform Integration: From aa to bb on f(x)f(x).

Linear function area representation

Step-by-Step Calculation of Area

  1. Identify the function f(x)f(x).
  2. Set Limits from aa to bb.
  3. Evaluate the definite integral.

Examples:

  • Linear Example: Integrate f(x)=xf(x) = x from 00 to 22; 02xdx=2\int_0^2 x \, dx = 2.

  • Polynomial Example: For f(x)=x2f(x) = x^2 from 11 to 33, compute by [x33]13\left[ \frac{x^3}{3} \right]_1^3.

Integration steps for a quadratic function

Signed Areas and Their Calculation

  • Signed Areas: Denotes the total area under a curve, where the area above the x-axis is positive and below is negative.

Calculation Example

  1. Determine Anti-derivative: For f(x)=x1f(x) = x - 1, F(x)=x22xF(x) = \frac{x^2}{2} - x.
  2. Apply Limits: 02(x1)dx=F(2)F(0)=0\int_0^2 (x - 1) \, dx = F(2) - F(0) = 0.

Graph illustrating signed areas

infoNote

Anti-derivative: Reverses differentiation to calculate signed areas.

Approximation Techniques

Introduction

  • Essential when exact integration proves challenging due to complexities involving non-linear or transcendental functions.

Methods

Rectangular Methods
  • Riemann Sums: Utilise rectangles to estimate areas.
    • Left/Right/Midpoint Riemann Sums offer varying measurement points.
Trapezoidal Rule
  • Improves rectangle approximations by employing trapezoids.
  • Useful for complex functions lacking straightforward anti-derivatives.

Aba2ni=1n[f(xi1)+f(xi)]A \approx \frac{b-a}{2n} \sum_{i=1}^{n}[f(x_{i-1}) + f(x_i)]

  • Example: Determine the area under f(x)=x2f(x) = x^2 on [0,2][0,2], n=4n=4 using the trapezoidal method.

Trapezoidal rule diagram

Example: Trapezoidal Rule with f(x)=x2f(x) = x^2

  1. Choose Intervals: Consider lines [0,1][0, 1] and [1,2][1, 2].
  2. Evaluate at endpoints; accumulate areas.

For example, with n=2n=2 (dividing [0,2][0,2] into two equal subintervals):

  • Endpoints are x0=0x_0=0, x1=1x_1=1, x2=2x_2=2
  • Function values are f(0)=0f(0)=0, f(1)=1f(1)=1, f(2)=4f(2)=4
  • Using the formula: A202(2)[(0+1)+(1+4)]=12[1+5]=3A \approx \frac{2-0}{2(2)}[(0+1) + (1+4)] = \frac{1}{2}[1 + 5] = 3
  • Exact value is 83\frac{8}{3}, so our approximation is reasonably close.

Improved approximation with trapezoids

Symmetry in Calculations

  • Symmetry in Functions: Simplifies calculations when working with even (f(x)=f(x)f(x)=f(-x)) and odd functions (f(x)=f(x)f(x)=-f(-x)).
  • Application: Reduces redundant integrations when symmetry is applicable.

Example

  • bbx2dx=20bx2dx\int_{-b}^{b} x^2 \, dx = 2 \int_{0}^{b} x^2 \, dx helps simplify calculations.
infoNote

Tip: Employ symmetry to ease calculations.

Fundamental Theorem of Calculus (FTC)

Explanation

  • Connection between differentiation and integration.
  • Formula: abf(x)dx=F(b)F(a)\int_{a}^{b} f(x) \, dx = F(b) - F(a)
    • F is an antiderivative of f.

Example

  • Polynomial: To evaluate 03(2x)dx\int_0^3 (2x) \, dx, use F(x)=x2F(x) = x^2. Solution: F(3)F(0)=3202=9F(3) - F(0) = 3^2 - 0^2 = 9

  • Trigonometric: For 0πsin(x)dx\int_0^{\pi} \sin(x) \, dx, apply F(x)=cos(x)F(x) = -\cos(x). Solution: cos(π)(cos(0))=(1)(1)=1+1=2-\cos(\pi) - (-\cos(0)) = -(-1) - (-1) = 1 + 1 = 2

Exam Tips

  • Always verify that limits are arranged with a<ba < b.
  • Use symmetry to streamline calculations.

Grasping these concepts and methods will turn integral calculus into a valuable tool for exams and practical applications.

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