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Chain Rule in Calculus Simplified Revision Notes

Revision notes with simplified explanations to understand Chain Rule in Calculus quickly and effectively.

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Chain Rule in Calculus

The chain rule is essential for differentiating intricate functions where one function is nested inside another, referred to as composite functions. This guide aims to assist you in understanding and applying the chain rule proficiently.

Composite Functions

  • Composite Functions: Merge two or more functions where the output of one function is utilised as the input for another.
    • Notation: f(g(x))f(g(x)) visually represents this composition.
    • Example: Given f(x)=x2f(x) = x^2 and g(x)=3x+1g(x) = 3x + 1, then f(g(x))=(3x+1)2f(g(x)) = (3x + 1)^2.
infoNote

Key Definition:

Composite Functions: An amalgamation of several functions, where outputs function as inputs for succeeding functions.

Diagram illustrating the concept of a composite function with nested functions.

The Chain Rule

  • Mathematical Notation:

    • If h(x)=f(g(x))h(x) = f(g(x)), then h(x)=f(g(x))g(x)h'(x) = f'(g(x)) \cdot g'(x).
    • Alternative Notation: dydx=dydududx\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}
  • Purpose: This rule is beneficial for differentiating functions nested within other functions, permitting differentiation of composite functions by considering each function individually.

Diagram illustrating function composition

Worked Examples

Example 1: Differentiating (3x+1)2(3x + 1)^2

  • Identify Functions:

    • Outer: f(u)=u2f(u) = u^2
    • Inner: g(x)=3x+1g(x) = 3x + 1
  • Differentiate:

    • f(u)=2uf'(u) = 2u
    • g(x)=3g'(x) = 3
  • Apply Chain Rule: h(x)=2(3x+1)3=18x+6h'(x) = 2(3x + 1) \cdot 3 = 18x + 6

chatImportant

Proficiency in the chain rule guarantees the comprehensive understanding and management of advanced calculus concepts.

Example 2: Differentiating (3x2+2)5(3x^2 + 2)^5

  • Identify Functions:

    • Outer: f(u)=u5f(u) = u^5
    • Inner: g(x)=3x2+2g(x) = 3x^2 + 2
  • Differentiate:

    • f(u)=5u4f'(u) = 5u^4
    • g(x)=6xg'(x) = 6x
  • Apply Chain Rule: dhdx=5(3x2+2)46x=30x(3x2+2)4\frac{dh}{dx} = 5(3x^2 + 2)^4 \cdot 6x = 30x(3x^2 + 2)^4

Common Mistakes and Tips

Typical Errors

  • Neglecting the Derivative of the Inner Function: Omitting multiplication by g(x)g'(x) can significantly alter the outcome.
  • Misidentifying Functions: Incorrectly determining which part is the inner versus the outer function can lead to errors.
  • Misapplication of the Rule: Incorrect sequence of differentiation steps can produce erroneous results; ensure each derivative is applied accurately.
infoNote

Properly identifying inner and outer functions is vital for the correct application of the chain rule.

Strategies

  • Use Visual Aids: Diagrams assist in clearly delineating the structure of functions.
  • Mnemonic Devices: "Inside first, then out!" is helpful for remembering the sequence.
  • Rechecking: A systematic review of each step ensures precision.

Practice Problems

Problems

  1. Differentiate f(x)=(x2+1)4f(x) = (x^2 + 1)^4.
  2. Differentiate g(x)=ln(5x2+2)g(x) = \ln(5x^2 + 2).
  3. Differentiate h(x)=sin(3x2+x)h(x) = \sin(3x^2+ x).

Solutions

Exercise 1 Solution:

  • Functions: outer f(u)=u4\text{outer } f(u) = u^4, inner g(x)=x2+1\text{inner } g(x) = x^2 + 1
  • dfdx=4(x2+1)32x=8x(x2+1)3\frac{df}{dx} = 4(x^2 + 1)^3 \cdot 2x = 8x(x^2 + 1)^3

Exercise 2 Solution:

  • Functions: outer f(u)=ln(u)\text{outer } f(u) = \ln(u), inner g(x)=5x2+2\text{inner } g(x) = 5x^2 + 2
  • dgdx=15x2+210x=10x5x2+2\frac{dg}{dx} = \frac{1}{5x^2 + 2} \cdot 10x = \frac{10x}{5x^2 + 2}

Exercise 3 Solution:

  • Functions: outer f(u)=sin(u)\text{outer } f(u) = \sin(u), inner g(x)=3x2+x\text{inner } g(x) = 3x^2 + x
  • dhdx=cos(3x2+x)(6x+1)\frac{dh}{dx} = \cos(3x^2 + x) \cdot (6x + 1)
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