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What is the mole fraction of 1.0 g of a compound of relative molecular mass 100.0 dissolved in 30.0 g of solvent of relative molecular mass 50.0? - AQA - A-Level Chemistry - Question 9 - 2021 - Paper 3

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What is the mole fraction of 1.0 g of a compound of relative molecular mass 100.0 dissolved in 30.0 g of solvent of relative molecular mass 50.0?

Worked Solution & Example Answer:What is the mole fraction of 1.0 g of a compound of relative molecular mass 100.0 dissolved in 30.0 g of solvent of relative molecular mass 50.0? - AQA - A-Level Chemistry - Question 9 - 2021 - Paper 3

Step 1

Calculate the moles of the compound

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Answer

To find the moles of the compound, we use the formula:

n=mMn = \frac{m}{M}

where:

  • mm is the mass of the compound (1.0 g)
  • MM is the molecular mass of the compound (100.0 g/mol)

Thus,

ncompound=1.0 g100.0 g/mol=0.01 moln_{compound} = \frac{1.0 \text{ g}}{100.0 \text{ g/mol}} = 0.01 \text{ mol}

Step 2

Calculate the moles of the solvent

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Answer

Similarly, for the solvent:

nsolvent=mMn_{solvent} = \frac{m}{M}

where:

  • mm is the mass of the solvent (30.0 g)
  • MM is the molecular mass of the solvent (50.0 g/mol)

Thus,

nsolvent=30.0 g50.0 g/mol=0.6 moln_{solvent} = \frac{30.0 \text{ g}}{50.0 \text{ g/mol}} = 0.6 \text{ mol}

Step 3

Calculate the mole fraction of the compound

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Answer

The mole fraction (XX) of the compound is calculated using the formula:

Xcompound=ncompoundncompound+nsolventX_{compound} = \frac{n_{compound}}{n_{compound} + n_{solvent}}

Substituting the values:

Xcompound=0.01 mol0.01 mol+0.6 mol=0.010.61≈0.016393X_{compound} = \frac{0.01 \text{ mol}}{0.01 \text{ mol} + 0.6 \text{ mol}} = \frac{0.01}{0.61} \approx 0.016393

So, the mole fraction is approximately 1.6×10−21.6 \times 10^{-2}.

Step 4

Final Answer

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Answer

The mole fraction of the compound is approximately 1.6×10−21.6 \times 10^{-2}, which corresponds to option B.

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