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Power $P$ is dissipated in a resistor of resistance $R$ carrying a direct current $I$ - AQA - A-Level Physics - Question 24 - 2022 - Paper 2
Question 24
Power $P$ is dissipated in a resistor of resistance $R$ carrying a direct current $I$. A second resistor of resistance $2R$ carries an alternating current with peak... show full transcript
Worked Solution & Example Answer:Power $P$ is dissipated in a resistor of resistance $R$ carrying a direct current $I$ - AQA - A-Level Physics - Question 24 - 2022 - Paper 2
Step 1
What is the power dissipated in the second resistor?
Answer
To find the power dissipated in the second resistor, we need to use the formula for power in a resistor:
For the first resistor with resistance and a direct current , the power is:
For the second resistor with resistance , carrying an alternating current with peak value , we substitute into the power formula:
Thus, since the power , we can express the power dissipated in the second resistor as:
Therefore, the power dissipated in the second resistor is .