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A voltmeter has a resistance of 4.0 kΩ and reads 1.0 V for every scale division on the meter - AQA - A-Level Physics - Question 24 - 2019 - Paper 1

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A voltmeter has a resistance of 4.0 kΩ and reads 1.0 V for every scale division on the meter. A power supply of emf 20 V and negligible internal resistance is conne... show full transcript

Worked Solution & Example Answer:A voltmeter has a resistance of 4.0 kΩ and reads 1.0 V for every scale division on the meter - AQA - A-Level Physics - Question 24 - 2019 - Paper 1

Step 1

What is the value of the resistor?

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Answer

To find the value of the resistor, we start by analyzing the voltmeter's reading and the given circuit attributes.

  1. Understanding the Circuit: The voltmeter (V_m) reads two divisions, which at 1 V per division means that Vm=2extVV_m = 2 ext{ V}. The total voltage from the power supply (V) is 20 V. Thus, we have the voltage across the resistor (R) as: VR=VVm=20extV2extV=18extVV_R = V - V_m = 20 ext{ V} - 2 ext{ V} = 18 ext{ V}

  2. Using Ohm's Law: The voltage across the resistor can also be expressed using Ohm's Law as: VR=IimesRV_R = I imes R where II is the current flowing through the circuit.

  3. Calculating the Current: The current through the voltmeter can be calculated since:

    • The total resistance in series is R+4.0extkΩR + 4.0 ext{ kΩ}.
    • The current II is then: I = rac{V}{R + 4.0kΩ}
  4. Setting up the Equation: Since we have: 18extV=IimesR18 ext{ V} = I imes R and substituting for I gives: 18 = rac{20}{R + 4.0} imes R

  5. Rearranging the Formula: To solve for R, we can rearrange the equation to: 18(R+4.0)=20R18(R + 4.0) = 20R which simplifies to: 18R+72=20R18R + 72 = 20R thus, 2R=722R = 72 leading to: R=36extkΩR = 36 ext{ kΩ}

  6. Conclusion: Therefore, the value of the resistor is 36 kΩ, corresponding to option B.

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