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Question 6
06.1 Name process X. 06.2 Name the process by which water is absorbed into plant roots. 06.3 Give two uses of water in plants. 1 2 06.4 The cow is more ... show full transcript
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Answer
Using the provided formula:
[ \text{energy conversion efficiency} = \frac{\text{energy used for growth}}{\text{energy input}} \times 100 ]
For grass: ( \text{energy input} = 1,700,000 \text{ kJ} )
( \text{energy used for growth (grass)} = 21800 \text{ kJ} )
[ \text{efficiency of grass} = \frac{21800}{1700000} \times 100 \approx 1.282% ]
Now, calculate how many times more efficient the cow is:
[ \text{times more efficient} = \frac{\text{efficiency of cow}}{\text{efficiency of grass}} = \frac{4.098}{1.282} \approx 3.196 ]
Thus, rounded to 3 significant figures, the cow is approximately 3.20 times more efficient than grass.
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