Photo AI

The speed limit on many roads in towns is 13.5 m/s Outside schools this speed limit is often reduced by one-third - AQA - GCSE Physics Combined Science - Question 6 - 2020 - Paper 2

Question icon

Question 6

The-speed-limit-on-many-roads-in-towns-is-13.5-m/s--Outside-schools-this-speed-limit-is-often-reduced-by-one-third-AQA-GCSE Physics Combined Science-Question 6-2020-Paper 2.png

The speed limit on many roads in towns is 13.5 m/s Outside schools this speed limit is often reduced by one-third. Calculate the reduced speed limit. Reduced spee... show full transcript

Worked Solution & Example Answer:The speed limit on many roads in towns is 13.5 m/s Outside schools this speed limit is often reduced by one-third - AQA - GCSE Physics Combined Science - Question 6 - 2020 - Paper 2

Step 1

Calculate the reduced speed limit.

96%

114 rated

Answer

To calculate the reduced speed limit, we need to reduce the original speed limit of 13.5 m/s by one-third. This is done as follows:

  1. Calculate one-third of 13.5 m/s: [ \frac{1}{3} \times 13.5 = 4.5 \text{ m/s} ]

  2. Subtract this value from the original speed limit: [ 13.5 - 4.5 = 9.0 \text{ m/s} ]

Thus, the reduced speed limit is 9.0 m/s.

Step 2

Explain one other advantage of a reduced speed limit.

99%

104 rated

Answer

One advantage of a reduced speed limit is that it can reduce stopping distances. When vehicles travel at lower speeds, the distance required to come to a complete stop is less, which enhances safety and reduces the likelihood of accidents. Additionally, a lower speed gives drivers more time to react to unforeseen circumstances, such as pedestrians or other obstacles.

Step 3

Calculate the minimum braking distance for the car at the speed it passed the speed camera.

96%

101 rated

Answer

We need to calculate the speed of the car first:

  1. Used the distance traveled and time: [ v = \frac{d}{t} = \frac{14 \text{ m}}{0.70 \text{ s}} = 20 \text{ m/s} ]

  2. Next, calculate the initial and final velocities, where the car is coming to a stop, so final velocity ( v_f = 0 ): [ u = 20 \text{ m/s},\ v_f = 0 ]

  3. Now use the formula relating acceleration (deceleration in this case), initial velocity, and distance: [ v^2 = u^2 + 2as\ 0 = (20)^2 + 2(-6.25)s\ ] Rearranging: [ 400 = 12.5s\ s = \frac{400}{12.5} = 32 ext{ m} ]

Thus, the minimum braking distance is 32 m.

Step 4

Explain why the empty van has a shorter stopping distance than the full van when driven at the same speed.

98%

120 rated

Answer

The empty van has a shorter stopping distance because it has less mass compared to the full van. When the mass is reduced, the braking force applied will result in a greater deceleration. This is due to Newton's second law, which states that acceleration is inversely proportional to mass for a given force. As a result, less braking distance is required to bring the lighter empty van to a stop compared to the heavier full van.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

Other GCSE Physics Combined Science topics to explore

;