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Which alkene reacts with hydrogen bromide to give 2-bromo-3-methylbutane as the major product? A (CH₃)₂C=CHCH₃ B CH₃CH=CHCH₂ C CH₃CH=C(CH₃)=CH₂ D (CH₃)₂C=CH₂ - AQA - A-Level Chemistry - Question 33 - 2019 - Paper 3

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Question 33

Which-alkene-reacts-with-hydrogen-bromide-to-give-2-bromo-3-methylbutane-as-the-major-product?--A-(CH₃)₂C=CHCH₃-B-CH₃CH=CHCH₂-C-CH₃CH=C(CH₃)=CH₂-D-(CH₃)₂C=CH₂-AQA-A-Level Chemistry-Question 33-2019-Paper 3.png

Which alkene reacts with hydrogen bromide to give 2-bromo-3-methylbutane as the major product? A (CH₃)₂C=CHCH₃ B CH₃CH=CHCH₂ C CH₃CH=C(CH₃)=CH₂ D (CH₃)₂C=CH₂

Worked Solution & Example Answer:Which alkene reacts with hydrogen bromide to give 2-bromo-3-methylbutane as the major product? A (CH₃)₂C=CHCH₃ B CH₃CH=CHCH₂ C CH₃CH=C(CH₃)=CH₂ D (CH₃)₂C=CH₂ - AQA - A-Level Chemistry - Question 33 - 2019 - Paper 3

Step 1

Identify the Major Product

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Answer

The major product stated is 2-bromo-3-methylbutane, which is derived from the addition of hydrogen bromide (HBr) to an alkene. This product indicates that the alkene structure should allow formation of a tertiary carbocation at carbon 3 upon protonation, leading to regioselectivity in the reaction.

Step 2

Analyze Each Alkene Option

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Answer

We will analyze each option to determine if it can produce the specified product:

  1. Option A: (CH₃)₂C=CHCH₃

    • Upon reaction with HBr, the proton adds to the alkene, forming a tertiary carbocation, which can lead to the formation of 2-bromo-3-methylbutane.
  2. Option B: CH₃CH=CHCH₂

    • This compound would form a secondary carbocation, which is less stable and thus would not lead primarily to the desired product.
  3. Option C: CH₃CH=C(CH₃)=CH₂

    • This option also leads to a secondary carbocation and will not yield the major product.
  4. Option D: (CH₃)₂C=CH₂

    • Similar to Option A, this alkene provides the tertiary carbocation upon addition of HBr, allowing for the formation of 2-bromo-3-methylbutane.

Step 3

Select the Correct Answer

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Answer

Based on the analysis, Option A: (CH₃)₂C=CHCH₃ leads to the formation of the desired major product: 2-bromo-3-methylbutane. Therefore, the correct answer is A.

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