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This question is about the isotopes of chromium - AQA - A-Level Chemistry - Question 2 - 2020 - Paper 1

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This question is about the isotopes of chromium. 0 2.1 Give the meaning of the term relative atomic mass. 0 2.2 A sample of chromium containing the isotopes 54Cr, ... show full transcript

Worked Solution & Example Answer:This question is about the isotopes of chromium - AQA - A-Level Chemistry - Question 2 - 2020 - Paper 1

Step 1

Give the meaning of the term relative atomic mass.

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Answer

Relative atomic mass is the average mass of an atom of an element compared to 1/12 the mass of a carbon-12 atom.

Step 2

Calculate the percentage abundance of each of the other two isotopes.

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Answer

Let the abundance of 54Cr be x% and the abundance of 53Cr be (100 - 86.1 - x)%. Using the equation for average atomic mass:

52.1=(x×54)+(86.1×52)+((10086.1x)×53)10052.1 = \frac{(x \times 54) + (86.1 \times 52) + ((100 - 86.1 - x) \times 53)}{100}

  1. Set the equation:
    • 52.1×100=x×54+86.1×52+(10086.1x)×5352.1 \times 100 = x \times 54 + 86.1 \times 52 + (100 - 86.1 - x) \times 53
  2. Solve for x:
    • x = 12.6 ext{%} for 54Cr and 100 - 86.1 - 12.6 = 1.3 ext{%} for 53Cr.

Step 3

State, in terms of the numbers of fundamental particles, one similarity and one difference between atoms of 54Cr and 53Cr.

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Answer

Similarity: Both 54Cr and 53Cr have the same number of protons (24).

Difference: 54Cr has 30 neutrons, while 53Cr has 29 neutrons.

Step 4

Give two reasons why it is necessary to ionise the isotopes of chromium before they can be analysed in a TOF mass spectrometer.

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Answer

  1. Ions are accelerated by an electric field, allowing them to gain kinetic energy.

  2. Ions create a current when hitting the detector, essential for measured analysis.

Step 5

Calculate the time, in s, for the 52Cr ion to travel down the flight tube to reach the detector.

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Answer

Using the formula for kinetic energy: KE=mv22KE = \frac{mv^2}{2} Rearranging it gives v=2×KEmv = \sqrt{\frac{2 \times KE}{m}} Where:

  • KE = 1.102 \times 10^{-3} J
  • m = 52 / 1000 kg (as 52Cr is approximately 52 g/mol and using the molar mass) After calculating speed, use: d=vtd = vt Where d is the distance (1.25 m) to find time: t=dvt = \frac{d}{v}

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