Which ionisation needs less energy than this process?
Mg(g) → Mg+(g) + e−
A Al(g) → Al+(g) + e−
B Ar(g) → Ar+(g) + e−
C Be(g) → Be+(g) + e−
D Mg+(g) → Mg2+(g) + e− - AQA - A-Level Chemistry - Question 16 - 2022 - Paper 3
Question 16
Which ionisation needs less energy than this process?
Mg(g) → Mg+(g) + e−
A Al(g) → Al+(g) + e−
B Ar(g) → Ar+(g) + e−
C Be(g) → Be+(g) + e−
D Mg+(g) → Mg2+(g) + e−
Worked Solution & Example Answer:Which ionisation needs less energy than this process?
Mg(g) → Mg+(g) + e−
A Al(g) → Al+(g) + e−
B Ar(g) → Ar+(g) + e−
C Be(g) → Be+(g) + e−
D Mg+(g) → Mg2+(g) + e− - AQA - A-Level Chemistry - Question 16 - 2022 - Paper 3
Step 1
A Al(g) → Al+(g) + e−
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Answer
The first ionization energy of Aluminium (Al) is lower than that of Magnesium (Mg) because Al has one more electron in the outer shell and thus can more easily lose an electron. Therefore, this process uses less energy.
Step 2
B Ar(g) → Ar+(g) + e−
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Answer
Argon (Ar) is a noble gas with a full outer shell, which means it requires more energy to remove an electron compared to Magnesium. Thus, this ionization process needs more energy.
Step 3
C Be(g) → Be+(g) + e−
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Answer
Beryllium (Be) has a higher ionization energy than Magnesium, as it has a greater effective nuclear charge, making it harder to remove the electron. Therefore, this process needs more energy.
Step 4
D Mg+(g) → Mg2+(g) + e−
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Answer
This ionization refers to the removal of a second electron from Magnesium. It generally requires more energy than the first ionization because the positive charge of Mg+ attracts the electron more strongly. Hence, more energy is needed.
