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A student plans an experiment to investigate the yield of propanoic acid when a sample of propan-1-ol is oxidised - AQA - A-Level Chemistry - Question 6 - 2021 - Paper 3

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A student plans an experiment to investigate the yield of propanoic acid when a sample of propan-1-ol is oxidised. Figure 4 shows the apparatus that the student pla... show full transcript

Worked Solution & Example Answer:A student plans an experiment to investigate the yield of propanoic acid when a sample of propan-1-ol is oxidised - AQA - A-Level Chemistry - Question 6 - 2021 - Paper 3

Step 1

Give two reasons why the apparatus shown in Figure 4 is not safe.

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Answer

  1. The flask is not clamped, posing a risk of it falling and breaking.
  2. The system is not sealed, which can lead to the escape of vapors and no control over pressure.

Step 2

Give one additional reagent that is needed to form any propanoic acid.

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Answer

Sulfuric acid needs to be added as a catalyst for the oxidation of propan-1-ol to form propanoic acid.

Step 3

State two more mistakes in the way the apparatus is set up in Figure 4.

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Answer

  1. The direction of water flow through the condenser is incorrect; it should enter from the bottom.
  2. A thermometer is not needed in this setup as it does not measure the necessary temperature accurately.

Step 4

State the purpose of the small glass beads in the flask in Figure 4.

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Answer

The small glass beads are used to prevent 'bumping' by providing a surface for the liquid to boil smoothly.

Step 5

After correcting the mistakes, the student heats a reaction mixture containing 6.50 g of propan-1-ol with an excess of the oxidising agent. The propanoic acid separated from the reaction mixture has a mass of 3.25 g. State the name of the technique used to separate the propanoic acid from the reaction mixture. Calculate the percentage yield of propanoic acid.

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Answer

The technique used to separate propanoic acid is fractional distillation. To calculate the percentage yield of propanoic acid, use the formula:

Percentageextyield=(Actual yieldTheoretical yield)×100Percentage \\ ext{ yield} = \left( \frac{\text{Actual yield}}{\text{Theoretical yield}} \right) \times 100

Theoretical yield for 6.50 g of propan-1-ol is based on its molar mass (60.1 g/mol) and stoichiometry:

  • Moles of propan-1-ol = \frac{6.50}{60.1} = 0.108 moles
  • Moles of propanoic acid produced = 0.108 moles
  • Mass of propanoic acid produced = 0.108 \times 74.1 = 8.00 g

Now, using the formula:

Percentage yield=(3.25g8.00g)×100=40.625%40.6%.\text{Percentage yield} = \left( \frac{3.25 \, \text{g}}{8.00 \,\text{g}} \right) \times 100 = 40.625\% \approx 40.6\%.

Step 6

State a simple chemical test that distinguishes the propanoic acid from the propan-1-ol. Give one observation for the test with each substance.

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Answer

Test: Add sodium carbonate.

Observation: For propanoic acid, effervescence of bubbles will occur due to the release of carbon dioxide. For propan-1-ol, no visible reaction will occur.

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