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This question is about equilibria - AQA - A-Level Chemistry - Question 1 - 2022 - Paper 1

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This question is about equilibria. 0.1.1. Give two features of a reaction in dynamic equilibrium. Feature 1 Feature 2 0.1.2. A gas-phase reaction is at equil... show full transcript

Worked Solution & Example Answer:This question is about equilibria - AQA - A-Level Chemistry - Question 1 - 2022 - Paper 1

Step 1

Give two features of a reaction in dynamic equilibrium.

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Answer

  1. The forward and reverse reactions proceed at equal rates.
  2. Concentrations of reactants and products remain constant over time.

Step 2

State what can be deduced about the chemical equation for this equilibrium.

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Answer

The reaction involves gases, and an increase in pressure favors the side with fewer moles of gas.

Step 3

Calculate the amount, in moles, of carbon monoxide present at equilibrium.

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Answer

At equilibrium, the total moles is 1.07 mol (0.430 mol CO + 0.860 mol H₂ - 0.110 mol CH₃OH). Thus, the moles of carbon monoxide can be calculated as follows:

Let x be the moles of CO at equilibrium:

Remaining H₂ = 0.860 - 2(x - (0.110/2))

Using the ideal gas law and total pressures, we find:

x + (0.860 - 2x) + 0.110 = 1.07 → 0.430 mol.

Step 4

Calculate the partial pressure, in kPa, of carbon monoxide in this equilibrium mixture.

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Answer

Using the formula for partial pressure, we have:

PCO=nCOntotal×PtotalP_{CO} = \frac{n_{CO}}{n_{total}} \times P_{total}

Substituting the values:
PCO=0.4301.07×250=100.9 kPaP_{CO} = \frac{0.430}{1.07} \times 250 = 100.9 \text{ kPa}

Step 5

Give an expression for the equilibrium constant (Kc) for this reaction.

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Answer

The equilibrium constant expression is given by:

Kc=[CH3OH][CO][H2]2K_c = \frac{[CH_3OH]}{[CO][H_2]^2}

Step 6

Calculate the partial pressure, in kPa, of hydrogen in this equilibrium mixture.

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Answer

From Table 1, using the relation for equilibrium constant:

Kc=PCH3OHPCOimesPH22K_c = \frac{P_{CH_3OH}}{P_{CO} imes P_{H_2}^2}

Rearranging gives:

PH22=PCH3OHKc×PCOP_{H_2}^2 = \frac{P_{CH_3OH}}{K_c \times P_{CO}}

Substituting the values:

PH2=5.45(1.15×102)×(125)=2.07extkPaP_{H_2} = \sqrt{\frac{5.45}{(1.15 \times 10^2) \times (125)}} = 2.07 ext{ kPa}

Step 7

Give the units for Kc.

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Answer

The units for Kc are mol/liter, or L/mol.

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