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For this reaction at equilibrium, which combination of temperature and pressure would give the greatest equilibrium yield of products? W(g) + X(g) ⇌ 2Y(g) + Z(g) ΔH = +447 kJ mol⁻¹ A High pressure and high temperature B High pressure and low temperature C Low pressure and high temperature D Low pressure and low temperature - AQA - A-Level Chemistry - Question 34 - 2018 - Paper 3

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Question 34

For-this-reaction-at-equilibrium,-which-combination-of-temperature-and-pressure-would-give-the-greatest-equilibrium-yield-of-products?--W(g)-+-X(g)-⇌-2Y(g)-+-Z(g)---ΔH-=-+447-kJ-mol⁻¹--A--High-pressure-and-high-temperature---B--High-pressure-and-low-temperature---C--Low-pressure-and-high-temperature---D--Low-pressure-and-low-temperature-AQA-A-Level Chemistry-Question 34-2018-Paper 3.png

For this reaction at equilibrium, which combination of temperature and pressure would give the greatest equilibrium yield of products? W(g) + X(g) ⇌ 2Y(g) + Z(g) ... show full transcript

Worked Solution & Example Answer:For this reaction at equilibrium, which combination of temperature and pressure would give the greatest equilibrium yield of products? W(g) + X(g) ⇌ 2Y(g) + Z(g) ΔH = +447 kJ mol⁻¹ A High pressure and high temperature B High pressure and low temperature C Low pressure and high temperature D Low pressure and low temperature - AQA - A-Level Chemistry - Question 34 - 2018 - Paper 3

Step 1

High pressure and high temperature

96%

114 rated

Answer

This combination would favor the production of products; however, the reaction is endothermic (ΔH = +447 kJ mol⁻¹), which means higher temperatures are actually beneficial for shifting the equilibrium to the right.

Step 2

High pressure and low temperature

99%

104 rated

Answer

High pressure will favor the side with fewer gas molecules. However, low temperatures are not ideal for an endothermic reaction.

Step 3

Low pressure and high temperature

96%

101 rated

Answer

Low pressure is not favorable since it could lead to lower yields of products, and although high temperature favors the endothermic reaction, the pressure factor is crucial.

Step 4

Low pressure and low temperature

98%

120 rated

Answer

This combination is the least favorable as both factors work against producing the products.

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